Question

Write all the factors of the following number 76.

Answer 1

Hint: This problem deals with factoring the given number. In number theory, integer factorization is the decomposition of a composite number into a product of smaller integers. If these factors are further restricted to prime numbers, the process is called prime factorization. We have to factorize the given number with its factors.

Complete step-by-step solution:
Factors are whole numbers that are multiplied together to produce another number. The original numbers are factors of the product number. If $c = a \times b$ then $a$ and $b$ are the factors of $c$.
Given a number, which is an integer, which is 76.
This number 76 is an even number.
Now factoring this number 76 until prime numbers.
Consider the number 76, as given below:
$ \Rightarrow 76 = 2 \times 38$
The given number 76 when divided by 2, gives the quotient 38, then 2 and 38 are the factors of the given number 76.
Also the obtained factor of 76 which is 38, can be further split into factors, which is given by:
$ \Rightarrow 76 = 2 \times 2 \times 19$
So the factor 38, when divided by 2, gives the quotient of 19, now we have three factors of 76.
Here 19 is a prime number, hence it cannot be further factorized into factors.
So the factors of 76 are 2, 2 and 19.

The factors of 76 are 2, 2 and 19.

Note: Please note that while factoring the given number into prime factors, this factorization is also called prime factorization. Prime factors are the prime numbers are the whole numbers which are greater 1, and they cannot be made by multiplying other whole numbers.