
How do you write a direct variation equation that relates x and y if y = -8 when x = 2, and how do you find y when x = 32?
Answer
550.2k+ views
Hint: Here, the given problem is based on the direct variation. When we have a direct variation, we can say that as the variable changes, the resulting value changes in the same and proportional manner. A direct variation between y and x is typically denoted by \[y=k x\], where k belongs to Real numbers. This means when x goes smaller y also tends to be smaller and vice versa. Here in this problem, by substituting the value of \[\left( x ,y \right)\] in the direct variation we get the value of k. the value of y can be found by substituting the value of k and given x = 32.
Complete step by step answer:
We know that, the direct variation between y and x is denoted by
\[y=k x\]……. (1)
Where the constant k belongs to real numbers.
We also know that the given point \[\left( x, y \right)\]is \[\left( 2,-8 \right)\]
Substituting the value of x and y in the direct equation (1), We get,
\[\begin{align}
& \Rightarrow \left( -8 \right)=k\left( 2 \right) \\
& \Rightarrow k=\dfrac{-8}{2} \\
& \Rightarrow k=-4 \\
\end{align}\]
Here, we found the constant value, k = -4.
Now we have to find y when x = 32,
Here, in the direct variation equation (1), we can substitute the value of k and given x = 32 to find y
We get,
\[\begin{align}
& \Rightarrow y=\left( -4 \right)32 \\
& \Rightarrow y=-128 \\
\end{align}\]
Therefore, the value of y is -128.
Note: Students may get confused about two values of x, here in this problem the first value of x is the point, which satisfies the required equation. The second value of x is to find the value of y from the direct variation equation. It is required to understand the concept of direct variation equation for these types of problems.
Complete step by step answer:
We know that, the direct variation between y and x is denoted by
\[y=k x\]……. (1)
Where the constant k belongs to real numbers.
We also know that the given point \[\left( x, y \right)\]is \[\left( 2,-8 \right)\]
Substituting the value of x and y in the direct equation (1), We get,
\[\begin{align}
& \Rightarrow \left( -8 \right)=k\left( 2 \right) \\
& \Rightarrow k=\dfrac{-8}{2} \\
& \Rightarrow k=-4 \\
\end{align}\]
Here, we found the constant value, k = -4.
Now we have to find y when x = 32,
Here, in the direct variation equation (1), we can substitute the value of k and given x = 32 to find y
We get,
\[\begin{align}
& \Rightarrow y=\left( -4 \right)32 \\
& \Rightarrow y=-128 \\
\end{align}\]
Therefore, the value of y is -128.
Note: Students may get confused about two values of x, here in this problem the first value of x is the point, which satisfies the required equation. The second value of x is to find the value of y from the direct variation equation. It is required to understand the concept of direct variation equation for these types of problems.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

