Write a balanced chemical reaction for the dehydration of concentrated sulphuric acid with sugar crystals.
Answer
565.8k+ views
Hint: Concentrated sulphuric acid is also known as a dehydrating agent. This is because it removes the water molecule from the compound to which it is added. The addition of water molecules to compounds is known as hydration while the removal of water molecules from that compound is known as dehydration.
Complete answer:
When we add water molecules to a compound then it is known as hydration of the compound. It is done by adding aqueous \[{H_2}O\] , whereas when we remove water molecules from the compound it is known as dehydration of the compound. It is done by using concentrated sulphuric acid. Such an agent which is used to remove water molecules is known as a dehydrating agent. Since we know that the molecular formula of sugar is \[{C_{12}}{H_{22}}{O_{11}}\] . Since it contains water molecules, therefore it will be dehydrated by removing all water molecules from sugar. This can be represented with the help of chemical equation as,
\[{C_{12}}{H_{22}}{O_{11}}{\text{ + n}}{{\text{H}}_2}{\text{S}}{{\text{O}}_4}{\text{ }}\xrightarrow{{}}{\text{ 12C + 11}}{{\text{H}}_2}{\text{O + n}}{{\text{H}}_2}{\text{S}}{{\text{O}}_4}\]
When we add sugar molecules with n-mole of concentrated sulphuric acid then we get twelve moles of carbon atom and 11 moles of water molecule, n-moles of sulphuric acid. Thus it behaves like a catalyst, it does not take part in reaction. We get carbon as a spongy substance after dehydration of sugar.
Note:
The number of moles of concentrated sulphuric acid remains conserved during reaction. Thus it behaves like a dehydrating agent by removing all water molecules from sugar. If a compound does not contain water molecules then concentrated sulphuric acid is used to bring unsaturation in the given compound.
Complete answer:
When we add water molecules to a compound then it is known as hydration of the compound. It is done by adding aqueous \[{H_2}O\] , whereas when we remove water molecules from the compound it is known as dehydration of the compound. It is done by using concentrated sulphuric acid. Such an agent which is used to remove water molecules is known as a dehydrating agent. Since we know that the molecular formula of sugar is \[{C_{12}}{H_{22}}{O_{11}}\] . Since it contains water molecules, therefore it will be dehydrated by removing all water molecules from sugar. This can be represented with the help of chemical equation as,
\[{C_{12}}{H_{22}}{O_{11}}{\text{ + n}}{{\text{H}}_2}{\text{S}}{{\text{O}}_4}{\text{ }}\xrightarrow{{}}{\text{ 12C + 11}}{{\text{H}}_2}{\text{O + n}}{{\text{H}}_2}{\text{S}}{{\text{O}}_4}\]
When we add sugar molecules with n-mole of concentrated sulphuric acid then we get twelve moles of carbon atom and 11 moles of water molecule, n-moles of sulphuric acid. Thus it behaves like a catalyst, it does not take part in reaction. We get carbon as a spongy substance after dehydration of sugar.
Note:
The number of moles of concentrated sulphuric acid remains conserved during reaction. Thus it behaves like a dehydrating agent by removing all water molecules from sugar. If a compound does not contain water molecules then concentrated sulphuric acid is used to bring unsaturation in the given compound.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

