
Which option correctly describes the equations for curves A and B, in the given graph of species-area relationship?
A) \[A - S = C{A^Z};LogC = LogC + Z\log A\]
B) \[A - LogS = LogC + Z\log A;B - S = C{A^Z}\]
C) \[A - LogC = LogS + Z\log A;B - S = C{A^Z}\]
D) \[A - S = C{A^Z};B - LogC = LogS + Z\log A\]

Answer
506.7k+ views
Hint:The connection between island region and number of species is notable: bigger islands contain a greater number of animal groups than littler islands. "Islands" can be utilized to allude not exclusively to parcels encompassed by water, however to natural surroundings islands also (lakes, timberland pieces, and so forth.
Complete answer:
Species - Area relationship: The essential thought of the model is that the quantity of species on an island is dictated by the migration of new species and the eradication of species effectively present; when these two rates balance each other, the species number is in harmony. A significant suspicion of the model is that the populace sizes for every species are relative to island size.
All taking everything into account (living space, decent variety and separation to the terrain or wellspring of colonizing species), on the off chance that we have two islands with similar migration rates, we would expect elimination rates on huge islands to be lower in light of their bigger populace sizes. Accordingly, bigger islands, at harmony, would have a more noteworthy number of species. Then again, on the off chance that we have two islands equivalent in size and territory decent variety yet at various good ways from the source, at that point termination rates would be required to be the equivalent, yet movement rates would be higher for the closer island, and at harmony the close to island would have more species.
From the given image it is clear that,
Curve A is $S = C{A^Z}$
Curve B is \[LogS = LogC + ZLogA\]
Thus, the correct answer is option (A).
Note:In this manner it is conceivable to make possibly valuable forecasts about the quantity of species on islands (or territory islands) when little data other than size is accessible. For preservation arranging, information on this relationship is of most extreme significance.
Complete answer:
Species - Area relationship: The essential thought of the model is that the quantity of species on an island is dictated by the migration of new species and the eradication of species effectively present; when these two rates balance each other, the species number is in harmony. A significant suspicion of the model is that the populace sizes for every species are relative to island size.
All taking everything into account (living space, decent variety and separation to the terrain or wellspring of colonizing species), on the off chance that we have two islands with similar migration rates, we would expect elimination rates on huge islands to be lower in light of their bigger populace sizes. Accordingly, bigger islands, at harmony, would have a more noteworthy number of species. Then again, on the off chance that we have two islands equivalent in size and territory decent variety yet at various good ways from the source, at that point termination rates would be required to be the equivalent, yet movement rates would be higher for the closer island, and at harmony the close to island would have more species.
From the given image it is clear that,
Curve A is $S = C{A^Z}$
Curve B is \[LogS = LogC + ZLogA\]
Thus, the correct answer is option (A).
Note:In this manner it is conceivable to make possibly valuable forecasts about the quantity of species on islands (or territory islands) when little data other than size is accessible. For preservation arranging, information on this relationship is of most extreme significance.
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