Question

Which one of the following is divisible by 3?
$(A) 27326$
$(B) 42356$
$(C) 73545$
$(D) 45326$

Answer 1

Hint: In this question we follow the process of the divisibility test by $3$ and check each and every option is divisible by that or not. Finally we get the required answer.

Complete step-by-step solution:
Divisibility test by $3$: A number is divisible by $3$ if the sum of its digits is divisible by $3.$
Here the numbers are $27326,42356,73545$ and $45326$
We have to find which among this is divisible by $3.$
Now we can say that a number is divisible by $3$ then we can write it sum of the digits also be divisible by $3.$
So we can check one by one option:
$A)27326$
Here we can add the given digits and we can write it as, $2 + 7 + 3 + 2 + 6 = 20$
But we get the answer is $20$ so it is not the multiple of the number $3.$
Therefore $(A)$cannot be the answer.
Now we take the option $B)42356$
Again we can add the given digits and we can write it as, $4 + 2 + 3 + 5 + 6 = 20$
But again $20$ is not the multiple of the number $3$.
Therefore $(B)$ cannot be the answer.
Again we take the option $(C)73545$
Now we can add the given digit and we get, $7 + 3 + 5 + 4 + 5 = 24$
Here, $24$ is the multiple of $3.$
Hence, option $(C)$ is the correct option.
Again we take the option $(D)45326$
Now we can add the given digit and we get, $4 + 5 + 3 + 2 + 6 = 20$
Here, $20$ is the multiple of $3.$
Hence, option $(D)$ is the wrong option.

Therefore the correct option is $(C)$ that is $73545$.

Note: The concept which we used in divisible by $3$ is the same as the divisible by $9$.
For example: $51984$
Now we can add the given digit and we get, $5 + 1 + 9 + 8 + 4 = 27$
Here, $27$is the multiple of $9$
Hence it is divisible by $9$
Make sure that you do not take $0$ in the first place because that will make the number a $4 - $ digit number which will be considered wrong as we are supposed to form a $5 - $ digit number.