
Which of the following statements is not correct about order of a reaction?
A.The order of a reaction can be a fractional number
B.Order of a reaction is experimentally determined quantity
C.The order of a reaction is always equal to the sum of the stoichiometric coefficients of reactants in the balanced chemical equation for a reaction
D.The order of a reaction is the sum of the powers of molar concentration of the reactants in the rate law expression.
Answer
569.7k+ views
Hint:The order is the sum of the powers to which the concentration of reactants is raised in a rate law expression. The rate of the reaction ${\text{aA + bB}} \to {\text{cC}}$ is ${\text{rate = [A}}{{\text{]}}^{\text{x}}}{\text{ + [B}}{{\text{]}}^{\text{y}}}$ where an order is x + y. On varying the concentration of any of the reactants, the rate of the reaction also changes.
Complete step by step answer:
There are different orders for different reactions. It can be zero order, first order, second order, pseudo-first-order, etc
The exponent on each concentration term is the order of the reaction in that particular reactant
Since it is experimentally determined, it can be integers, fractions.
${\text{xA + yB}} \to {\text{P}}$ , ${\text{rate = k[A}}{{\text{]}}^{\text{p}}}{{\text{[B]}}^{\text{q}}}$ , we could see here that the stoichiometric coefficient and the power terms are different.
${\text{2}}{{\text{N}}_{\text{2}}}{{\text{O}}_{\text{5}}} \to {\text{4N}}{{\text{O}}_{\text{2}}}{\text{ + }}{{\text{O}}_{\text{2}}}$
Rate, ${\text{r = k[}}{{\text{N}}_{\text{2}}}{{\text{O}}_{\text{5}}}{\text{]}}$
It is a first-order reaction that is not equal to the stoichiometry of the reactants in a balanced chemical equation.
Now on checking the options, the order of a reaction can be a fractional number.
The order of a reaction is experimentally determined.
order is the sum of the powers to which the concentration of reactants is raised in a rate law expression.
Therefore, options A, B, and D have correct statements.
And option C is an incorrect statement.
Hence, the correct option is (C).
Note:In very few cases the experimentally determined powers on the concentration term in a rate law are equal to the stoichiometric coefficient from a balanced equation. But this cannot be generalized.
${\text{2NO + }}{{\text{O}}_{\text{2}}} \to {\text{2N}}{{\text{O}}_{\text{2}}}$
${\text{rate = k[NO}}{{\text{]}}^{\text{2}}}{\text{[}}{{\text{O}}_{\text{2}}}{\text{]}}$ which is equal to the stoichiometric coefficient from the balanced equation.
The order is different from molecularity because molecularity is not an experimentally determined value. It is the number of reacting species.
Complete step by step answer:
There are different orders for different reactions. It can be zero order, first order, second order, pseudo-first-order, etc
The exponent on each concentration term is the order of the reaction in that particular reactant
Since it is experimentally determined, it can be integers, fractions.
${\text{xA + yB}} \to {\text{P}}$ , ${\text{rate = k[A}}{{\text{]}}^{\text{p}}}{{\text{[B]}}^{\text{q}}}$ , we could see here that the stoichiometric coefficient and the power terms are different.
${\text{2}}{{\text{N}}_{\text{2}}}{{\text{O}}_{\text{5}}} \to {\text{4N}}{{\text{O}}_{\text{2}}}{\text{ + }}{{\text{O}}_{\text{2}}}$
Rate, ${\text{r = k[}}{{\text{N}}_{\text{2}}}{{\text{O}}_{\text{5}}}{\text{]}}$
It is a first-order reaction that is not equal to the stoichiometry of the reactants in a balanced chemical equation.
Now on checking the options, the order of a reaction can be a fractional number.
The order of a reaction is experimentally determined.
order is the sum of the powers to which the concentration of reactants is raised in a rate law expression.
Therefore, options A, B, and D have correct statements.
And option C is an incorrect statement.
Hence, the correct option is (C).
Note:In very few cases the experimentally determined powers on the concentration term in a rate law are equal to the stoichiometric coefficient from a balanced equation. But this cannot be generalized.
${\text{2NO + }}{{\text{O}}_{\text{2}}} \to {\text{2N}}{{\text{O}}_{\text{2}}}$
${\text{rate = k[NO}}{{\text{]}}^{\text{2}}}{\text{[}}{{\text{O}}_{\text{2}}}{\text{]}}$ which is equal to the stoichiometric coefficient from the balanced equation.
The order is different from molecularity because molecularity is not an experimentally determined value. It is the number of reacting species.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

