
Which of the following salts will not undergo hydrolysis in water?
A. Sodium sulphate
B. Ammonium sulphate
C. Aluminium sulphate
D. All the salts will undergo hydrolysis
Answer
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Hint: All the salts containing strong acids and strong bases never hydrolyse under water. We will keep this in mind while solving the question and examine all the questions one by one. Refer to the solution below for further details.
Complete step-by-step answer:
Biological hydrolysis is a division of biomolecules where a molecule of water is absorbed to break the bigger molecule into pieces. Where a carbohydrate is separated through hydrolysis into the molecules of the sugar portion (saccharification, for example, is broken down into glucose and fructose). Hydrolysis reactions will transform a condensation reaction into a larger one where two molecules bind together and expel a molecule of water. While hydrolysis requires hydrogen to break down while hydrogen and all other solvents are eliminated by condensation. Hydrolyses are two of the hydration reactions.
Rest of the salts including strong acid and weak base, weak acid and strong base, weak acid and weak base will get hydrolysed under water.
Option A is sodium sulphate-
$ \Rightarrow N{a_2}S{O_4} \to NaOH + {H_2}S{O_4}$
As we can see from above, NaOH is a strong base and ${H_2}S{O_4}$ is a strong acid. Thus, it will not hydrolyse under water.
Option B is ammonium sulphate-
$ \Rightarrow {\left( {N{H_4}} \right)_2}S{O_4} \to N{H_4}OH + {H_2}S{O_4}$
As we can see from the above reaction, $N{H_4}OH$ is a weak base and ${H_2}S{O_4}$ is a strong acid. Thus, it will hydrolyse under water.
Option C is aluminium sulphate
$ \Rightarrow A{l_2}{\left( {S{O_4}} \right)_3} \to Al{\left( {OH} \right)_3} + {H_2}S{O_4}$
As we can see from the above reaction, $Al{\left( {OH} \right)_3}$ is a weak base and ${H_2}S{O_4}$ is a strong acid. Thus, it will hydrolyse under water.
Hence, option A is the correct option.
Note: Hydrolysis is a chemical reaction that splits one of more chemical bonds through a water molecule. The expression is commonly used to use water as a nucleophile for replacement, removal and solvation reactions.
Complete step-by-step answer:
Biological hydrolysis is a division of biomolecules where a molecule of water is absorbed to break the bigger molecule into pieces. Where a carbohydrate is separated through hydrolysis into the molecules of the sugar portion (saccharification, for example, is broken down into glucose and fructose). Hydrolysis reactions will transform a condensation reaction into a larger one where two molecules bind together and expel a molecule of water. While hydrolysis requires hydrogen to break down while hydrogen and all other solvents are eliminated by condensation. Hydrolyses are two of the hydration reactions.
Rest of the salts including strong acid and weak base, weak acid and strong base, weak acid and weak base will get hydrolysed under water.
Option A is sodium sulphate-
$ \Rightarrow N{a_2}S{O_4} \to NaOH + {H_2}S{O_4}$
As we can see from above, NaOH is a strong base and ${H_2}S{O_4}$ is a strong acid. Thus, it will not hydrolyse under water.
Option B is ammonium sulphate-
$ \Rightarrow {\left( {N{H_4}} \right)_2}S{O_4} \to N{H_4}OH + {H_2}S{O_4}$
As we can see from the above reaction, $N{H_4}OH$ is a weak base and ${H_2}S{O_4}$ is a strong acid. Thus, it will hydrolyse under water.
Option C is aluminium sulphate
$ \Rightarrow A{l_2}{\left( {S{O_4}} \right)_3} \to Al{\left( {OH} \right)_3} + {H_2}S{O_4}$
As we can see from the above reaction, $Al{\left( {OH} \right)_3}$ is a weak base and ${H_2}S{O_4}$ is a strong acid. Thus, it will hydrolyse under water.
Hence, option A is the correct option.
Note: Hydrolysis is a chemical reaction that splits one of more chemical bonds through a water molecule. The expression is commonly used to use water as a nucleophile for replacement, removal and solvation reactions.
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