Question

Which of the following reagents does not give oxygen as one of the products during oxidation with ozone.
A.$Hg$
B.$S{O_2}$
C.$SnC{l_2}/HCL$
D.${H_2}S$

Answer 1

Hint: Ozone or trioxygen, is an inorganic molecule with the chemical formula ${O_3}$. It is a pale blue gas with a distinctively pungent smell. It is an allotrope of oxygen that is much less stable than the diatomic allotrope ${O_2}$, breaking down in the lower atmosphere to ${O_2}$

Complete Answer:
In this question for a better understanding we have to separately solve each and every option and see if the oxygen is given out as a product or not. Now first we need to look into the first option that is $Hg$
$2Hg + {O_3} \to H{g_2}O + {O_2}$
As we see in the above equation it is clear that this cannot be the right option as oxygen is given out as a product. Now, moving into next option, that is $S{O_2}$
$3S{O_2} + {O_3} \to 3S{O_3}$
Now, as we look into the above equation it becomes clear that this could be the right option as oxygen is not given as the product. Now when we move onto the next option that is $SnC{l_2}/HCL$
$3SnC{l_2} + 6HCl + {O_3} \to 3SnC{l_4} + 3{H_2}O$
Now again, this becomes clear that the equation above is also the right option as the oxygen is not given as the product. Now at last when we move into the last option that is ${H_2}S$
$\begin{gathered}
  {H_2}S + {O_3} \to S + {O_2} + {H_2}O \\
    \\
\end{gathered} $
This won’t be the right option as oxygen is given out as a product in the equation.

Hence, the right options are (B) and (C).

Note: in the question as we study properly it is said the reagent that does not give out oxygen as the product. Sometimes it is said that reading the question properly will get extra credit as well because the hunt for the question often stays in the question itself. Hence we also need to concentrate on the equation because it is where we get to know the right option.