Which of the following of the given numbers is the greatest number ?
A. 7212
B. 7122
C. 7211
D. 7221
Answer
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Hint: Let us compare all the digits of the given numbers starting from the leftmost digit and going towards right most digit. So, that we can get the greatest number.
As we know that if the total number of digits in one number is more than the total number of the digits in another number. Then the first number will be greater than the second number.
Complete step-by-step solution:
But if they both have the same number of digits then we have to compare their digits to get the greater number.
First, we compare the leftmost digit, if the leftmost digit of the first number is greater than the leftmost digit of another number then the number with greater leftmost digit will be greater otherwise, we compare their second digit and this process goes on till we get different digits (i.e. greater number).
So, now let us find the greatest number of the given numbers.
As we can see that all four numbers 7212, 7122, 7211 and 7221 have their first digit the same and that is equal to 7.
So, now comparing their second digit,
Second digit of 7122 is 1 and the second digit of all other numbers are the same and that is 2. So, 7122 is the smallest number.
Now compare the third digit of 7212, 7211 and 7221.
As we can see that 7212 and 7211 has its third digit equal to 1 and the third digit of 7221 is 2. So, 7221 is greater than 7212 and 7211.
So, the greatest number is 7221.
Hence, the correct option will be D.
Note: Whenever we come up with this type of problem then we should take care like for numbers 1159 and 01289. 01289 has a greater number of digits than 1159 but 01289 is not a greater number than 1159 because if the first digit of a number is zero, then the number is written without the first digit like 01289 = 1289. And then we had to compare digits of both the numbers 1159 and 1289 till we did not get the different digit. This will be the easiest and efficient way to find the greatest or smallest number from the given numbers.
As we know that if the total number of digits in one number is more than the total number of the digits in another number. Then the first number will be greater than the second number.
Complete step-by-step solution:
But if they both have the same number of digits then we have to compare their digits to get the greater number.
First, we compare the leftmost digit, if the leftmost digit of the first number is greater than the leftmost digit of another number then the number with greater leftmost digit will be greater otherwise, we compare their second digit and this process goes on till we get different digits (i.e. greater number).
So, now let us find the greatest number of the given numbers.
As we can see that all four numbers 7212, 7122, 7211 and 7221 have their first digit the same and that is equal to 7.
So, now comparing their second digit,
Second digit of 7122 is 1 and the second digit of all other numbers are the same and that is 2. So, 7122 is the smallest number.
Now compare the third digit of 7212, 7211 and 7221.
As we can see that 7212 and 7211 has its third digit equal to 1 and the third digit of 7221 is 2. So, 7221 is greater than 7212 and 7211.
So, the greatest number is 7221.
Hence, the correct option will be D.
Note: Whenever we come up with this type of problem then we should take care like for numbers 1159 and 01289. 01289 has a greater number of digits than 1159 but 01289 is not a greater number than 1159 because if the first digit of a number is zero, then the number is written without the first digit like 01289 = 1289. And then we had to compare digits of both the numbers 1159 and 1289 till we did not get the different digit. This will be the easiest and efficient way to find the greatest or smallest number from the given numbers.
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