Question

which of the following method is neither meant for the synthesis nor for the separation of amines:
A. Curtius Reaction
B. Wurtz Reaction
C. Hoffman Reaction
D. Hinsberg Reaction

Answer 1

Hint: The mechanism of this reaction involves free radicals, allowing for the possibility of side reactions that lead to the formation of alkenes as the product.

Compete step by step answer:
->Option 1st: In the Curtius adjustment, an acyl azide is warmed, and an isocyanate is shaped. In the Curtius, the isocyanate can be separated, yet is generally changed further into different species such a carbamate, a urea, or (through decarboxylation, as in the Hofmann) to an amine

->Option 2nd: The Wurtz reaction is a valuable reaction in the fields of natural science and organometallic science for the arrangement of alkanes. In this reaction, two distinctive alkyl halides are coupled to yield a more extended alkane chain with the assistance of sodium and dry ether arrangement.
Wurtz reaction is used to produce alkanes from alkyl halides.
\[2RX+2Na\to R-R+2NaX\]
Example:
\[2C{{H}_{3}}Cl+2Na\to {{C}_{2}}{{H}_{6}}+2NaCl\]
So, Wurtz reaction has nothing to do with amines.

->Option 3rd: When an amide is treated with bromine in an aqueous or ethanolic solution of sodium hydroxide, degradation of amide takes place to the generation of primary amine. This reaction elaborating degradation of amide and is famously known as Hoffmann bromamide degradation reaction.

->Option 4th: The Hinsberg reaction is a test for the observation of primary, secondary and tertiary amines. ... A primary amine will frame a solvent sulfonamide salt. Acidification of this salt at that point accelerates the sulfonamide of the essential amine. A secondary amine in a similar response will straightforwardly frame an insoluble sulfonamide.
In Wurtz reaction, alkyl halide reacts with sodium metal in the presence of dry ether to give alkane.

The correct option is B. Wurtz Reaction

Note:
Wurtz’s reaction is an organic chemical coupling reaction wherein sodium metal is reacted with two alkyl halides in the environment provided by a solution of dry ether in order to form a higher alkane along with a compound containing sodium and the halogen.