
Which of the following chemical reactions is/are involved in the development of the photographic plate?
A. ${C_6}{H_4}{(OH)_2} + 2AgBr \to 2Ag + {C_6}{H_4}{O_2} + 2HBr$
B. $AgBr + 2N{a_2}{S_2}{O_3} \to N{a_3}[Ag{\left( {{S_2}{O_3}} \right)_2}] + NaBr$
C. $AgBr + 2N{H_3}(aq) \to [Ag{(N{H_3})_2}]Br$
D. $2AgBr + N{a_2}{S_2}{O_3} \to A{g_2}{S_2}{O_3} + 2NaBr$
Answer
556.8k+ views
Hint: The chemical compounds have many practical uses apart from the chemical reactions that take place in the labs. Some elements have the property to capture light and are used in the photography industry. This type of chemical reaction is taken advantage of for the different needed procedures to happen.
Complete step by step answer:
For the formation of the photographic plate, the light-sensitive emulsion of silver salt is coated on a glass plate, which is typically thinner than a glass plate. Its modern version involves the use of plastic films for the application of these chemicals and the formation of photographic films.
The development of the photographic plate involves the steps of the formation of the photographic film and the fixing of the photographic film by the removal of excess material.
The first step involves making the positive/negative of the photographic film. This process involves the reaction as
${C_6}{H_4}{(OH)_2} + 2AgBr \to 2Ag + {C_6}{H_4}{O_2} + 2HBr$
The second step involves the fixing of the photographic film by the removal of $AgBr$ which is unreduced in the form of the soluble product. The above step involves the reaction as:
$AgBr + 2N{a_2}{S_2}{O_3} \to N{a_3}[Ag{\left( {{S_2}{O_3}} \right)_2}] + NaBr$.
So, the correct answer is Option A,B.
Note: These photographic plates were used before the production of photographic film and were majorly used by the astronomers for researching the cosmic events by the pictures that they captured by these photographic plates. These images were then used for the study of the phenomenon and galaxies that were not visible for studies back then.
Complete step by step answer:
For the formation of the photographic plate, the light-sensitive emulsion of silver salt is coated on a glass plate, which is typically thinner than a glass plate. Its modern version involves the use of plastic films for the application of these chemicals and the formation of photographic films.
The development of the photographic plate involves the steps of the formation of the photographic film and the fixing of the photographic film by the removal of excess material.
The first step involves making the positive/negative of the photographic film. This process involves the reaction as
${C_6}{H_4}{(OH)_2} + 2AgBr \to 2Ag + {C_6}{H_4}{O_2} + 2HBr$
The second step involves the fixing of the photographic film by the removal of $AgBr$ which is unreduced in the form of the soluble product. The above step involves the reaction as:
$AgBr + 2N{a_2}{S_2}{O_3} \to N{a_3}[Ag{\left( {{S_2}{O_3}} \right)_2}] + NaBr$.
So, the correct answer is Option A,B.
Note: These photographic plates were used before the production of photographic film and were majorly used by the astronomers for researching the cosmic events by the pictures that they captured by these photographic plates. These images were then used for the study of the phenomenon and galaxies that were not visible for studies back then.
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