Which number cannot represent a probability?
(A) \[\dfrac{2}{3}\]
(B) \[1.5\]
(C) \[15\% \]
(D) \[0.7\]
Answer
522.9k+ views
Hint: In the question, we are given a certain set of numbers and we have to find which number cannot be a probability. For this firstly we should understand that in an experiment, probability is the measure of likelihood of an event to occur. Probability is a value between (and including) zero and one. If \[P\left( E \right)\] represents the probability of an event, then we can write \[0 \leqslant P\left( E \right) \leqslant 1\] .On the basis of these concepts we will check each option and find whether it can be a probability or not.
Complete step-by-step answer:
We have to find which one of the given options can not be a probability of an event. Let us recollect what a probability of an event means. The probability is the measure of likelihood of an event to occur. The important rule of probability is that probability is a value between (and including) zero and one i.e., if \[P\left( E \right)\] represents the probability of an event, then we can write \[0 \leqslant P\left( E \right) \leqslant 1\]
Now let us consider each of the options.
In the option (a), the first number we are given is \[\dfrac{2}{3}\] . Let us divide \[2\] by \[3\]
\[ \Rightarrow \dfrac{2}{3} = 0.667\]
Here we can see that \[0.667\]is between \[0\] and \[1\] .
\[\therefore \dfrac{2}{3}\] can be the probability of an event.
Now from option (b), the given number is \[1.5\]
Here we can see that \[1.5 > 1\] and therefore violate the condition. Hence, \[1.5\] cannot be the probability of an event.
Now, let us verify option (c), the given term is \[15\% \]
\[ \Rightarrow 15\% = \dfrac{{15}}{{100}} = 0.15\]
Here we can see that \[0.15\]is between \[0\] and \[1\] .
\[\therefore 15\% \] can be the probability of an event.
Now, let us consider option (d), the given number is \[0.7\]
Here we can see that \[0.7\]is between \[0\] and \[1\] .
\[\therefore 0.7\] can be the probability of an event.
Thus, from the above calculation we observe that only \[1.5\] can not be the probability of an event.
So, the correct answer is “Option C”.
Note: Students must note that in the given condition \[0 \leqslant P\left( E \right) \leqslant 1\] , \[0\] and \[1\] are included. Probability of an event, \[P\left( E \right) = 0\] if and only if \[E\] is an impossible event. And probability of an event, \[P\left( E \right) = 1\] if and only if \[E\] is a certain event. And the sum of probabilities will always be equal to \[1\]
Complete step-by-step answer:
We have to find which one of the given options can not be a probability of an event. Let us recollect what a probability of an event means. The probability is the measure of likelihood of an event to occur. The important rule of probability is that probability is a value between (and including) zero and one i.e., if \[P\left( E \right)\] represents the probability of an event, then we can write \[0 \leqslant P\left( E \right) \leqslant 1\]
Now let us consider each of the options.
In the option (a), the first number we are given is \[\dfrac{2}{3}\] . Let us divide \[2\] by \[3\]
\[ \Rightarrow \dfrac{2}{3} = 0.667\]
Here we can see that \[0.667\]is between \[0\] and \[1\] .
\[\therefore \dfrac{2}{3}\] can be the probability of an event.
Now from option (b), the given number is \[1.5\]
Here we can see that \[1.5 > 1\] and therefore violate the condition. Hence, \[1.5\] cannot be the probability of an event.
Now, let us verify option (c), the given term is \[15\% \]
\[ \Rightarrow 15\% = \dfrac{{15}}{{100}} = 0.15\]
Here we can see that \[0.15\]is between \[0\] and \[1\] .
\[\therefore 15\% \] can be the probability of an event.
Now, let us consider option (d), the given number is \[0.7\]
Here we can see that \[0.7\]is between \[0\] and \[1\] .
\[\therefore 0.7\] can be the probability of an event.
Thus, from the above calculation we observe that only \[1.5\] can not be the probability of an event.
So, the correct answer is “Option C”.
Note: Students must note that in the given condition \[0 \leqslant P\left( E \right) \leqslant 1\] , \[0\] and \[1\] are included. Probability of an event, \[P\left( E \right) = 0\] if and only if \[E\] is an impossible event. And probability of an event, \[P\left( E \right) = 1\] if and only if \[E\] is a certain event. And the sum of probabilities will always be equal to \[1\]
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Class 12 Question and Answer - Your Ultimate Solutions Guide

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Sulphuric acid is known as the king of acids State class 12 chemistry CBSE

Why is the cell called the structural and functional class 12 biology CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

