
What is a Silver Nitrate Test?
Answer
594.3k+ views
Hint: Before moving on with the description of the Silver Nitrate Test, we should know the aim of the Silver Nitrate Test. The main of the test is to find out which halogen is present in a suspected halogenoalkane. Once we know the aim of the Silver Nitrate Test, we can move to the detail of the process.
Complete step-by-step answer:
The most effective way to find the suspected halogenoalkane is to do a substitution reaction which turns the halogen into a halide ion, and then to test for that ion with silver nitrate solution.
The basic structure of silver nitrate is given below.
The solution is first acidified by adding dilute \[\text{HN}{{\text{O}}_{\text{3}}}\] followed by silver nitrate solution.
\[\text{N}{{\text{H}}_{\text{3}}}\]${{\text{F}}^{-}}\text{,C}{{\text{l}}^{-}}\text{,B}{{\text{r}}^{-}}\text{ }\!\!\And\!\!\text{ }{{\text{I}}^{-}}$ react as given below:
$\text{A}{{\text{g}}^{+}}\text{(aq)+}{{\text{F}}^{-}}\text{(aq)}\xrightarrow{{}}\text{AgF}$ (No precipitate as it is soluble)
$\text{A}{{\text{g}}^{+}}\text{(aq)+C}{{\text{l}}^{-}}\text{(aq)}\xrightarrow{{}}\text{AgCl(s)}$ (white precipitate)
$\text{A}{{\text{g}}^{+}}\text{(aq)+B}{{\text{r}}^{-}}\text{(aq)}\xrightarrow{{}}\text{AgBr(s)}$ (pale cream precipitate)
$\text{A}{{\text{g}}^{+}}\text{(aq)+}{{\text{I}}^{-}}\text{(aq)}\xrightarrow{{}}\text{AgI(s)}$ (pale yellow precipitate)
The precipitate is treated with \[\text{N}{{\text{H}}_{\text{3}}}\] solution to confirm the halide. The following observation is done.
\[\text{AgCl }\to \] dissolves to give a colourless solution.
\[\text{AgBr}\to \] dissolves in conc. \[\text{N}{{\text{H}}_{\text{3}}}\] to give a colourless solution.
\[\text{AgI}\to \] insoluble in \[\text{N}{{\text{H}}_{\text{3}}}\] of any concentration.
The purpose of adding the dilute nitric acid is the removal of other ions that might also give a confusing precipitate with silver nitrate.
The purpose for the addition of ammonia is to form a complex ion with silver (I) ions which then allows the precipitate to redissolve.
Note: We should know that silver nitrate in as a compound is a prescription topical solution which is used for treating wounds and burns on the skin as an anti - infective agent.
Complete step-by-step answer:
The most effective way to find the suspected halogenoalkane is to do a substitution reaction which turns the halogen into a halide ion, and then to test for that ion with silver nitrate solution.
The basic structure of silver nitrate is given below.
The solution is first acidified by adding dilute \[\text{HN}{{\text{O}}_{\text{3}}}\] followed by silver nitrate solution.
\[\text{N}{{\text{H}}_{\text{3}}}\]${{\text{F}}^{-}}\text{,C}{{\text{l}}^{-}}\text{,B}{{\text{r}}^{-}}\text{ }\!\!\And\!\!\text{ }{{\text{I}}^{-}}$ react as given below:
$\text{A}{{\text{g}}^{+}}\text{(aq)+}{{\text{F}}^{-}}\text{(aq)}\xrightarrow{{}}\text{AgF}$ (No precipitate as it is soluble)
$\text{A}{{\text{g}}^{+}}\text{(aq)+C}{{\text{l}}^{-}}\text{(aq)}\xrightarrow{{}}\text{AgCl(s)}$ (white precipitate)
$\text{A}{{\text{g}}^{+}}\text{(aq)+B}{{\text{r}}^{-}}\text{(aq)}\xrightarrow{{}}\text{AgBr(s)}$ (pale cream precipitate)
$\text{A}{{\text{g}}^{+}}\text{(aq)+}{{\text{I}}^{-}}\text{(aq)}\xrightarrow{{}}\text{AgI(s)}$ (pale yellow precipitate)
The precipitate is treated with \[\text{N}{{\text{H}}_{\text{3}}}\] solution to confirm the halide. The following observation is done.
\[\text{AgCl }\to \] dissolves to give a colourless solution.
\[\text{AgBr}\to \] dissolves in conc. \[\text{N}{{\text{H}}_{\text{3}}}\] to give a colourless solution.
\[\text{AgI}\to \] insoluble in \[\text{N}{{\text{H}}_{\text{3}}}\] of any concentration.
The purpose of adding the dilute nitric acid is the removal of other ions that might also give a confusing precipitate with silver nitrate.
The purpose for the addition of ammonia is to form a complex ion with silver (I) ions which then allows the precipitate to redissolve.
Note: We should know that silver nitrate in as a compound is a prescription topical solution which is used for treating wounds and burns on the skin as an anti - infective agent.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

