
What is $250$ divided by $3$?
Answer
519.9k+ views
Hint: Here we have to divide $250$ by 3. Since we know if we have to divide any integer with $3$ completely, then we have to check whether the sum of the given integer is divisible by $3$ or not.
Here the given integer is $250$, now the sum of $250$ is $250=2+5+0=7$ here we can see easily $7$ is not divisible by $3$. So we will not get an integer result when dividing $250$ by $3$. So to solve this we will use a long division method.
Complete step by step answer:
In mathematics, long division is a method used for dividing larger numbers into groups or parts. Long division helps in breaking the division problem into a sequence of easier steps. Just like all division problems, a large number is divided by another number which is called the divisor, and the result called the quotient and sometimes remainder also left.
Here we have to divide $250$ by $3$, using long division method
Here $3$ is divisor and $250$ is dividend, then by long division method.
The steps which we have to follow are:
1 Divide the tens column dividend by the divisor.
2 Multiply the divisor by the quotient in the tens place column.
3 Subtract the product from the divisor.
4 Bring down the dividend in the ones column and repeat.
$\begin{align}
& 3\overset{83.333}{\overline{\left){250.000}\right.}} \\
& -24 \\
& \_\_\_\_ \\
& \,\,\,\, 10 \\
& \,\,-9 \\
& \_\_\_\_\_ \\
& \,\,\,\,\,\,\,10 \\
& \,\,\,\,\,-9 \\
& \_\_\_\_\_\_\_ \\
& \,\,\,\,\,\,\,\,\,\,10 \\
& \,\,\,\,\,\,\,\,-9 \\
& \_\_\_\_\_\_\_\_ \\
& \,\,\,\,\,\,\,\,\,\,\,\,\,10 \\
& \,\,\,\,\,\,\,\,\,\,\,-9 \\
& \_\_\_\_\_\_\_\_\ \\
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,1 \\
\end{align}$
Hence, we get the remainder $1$ and the quotient is $83.333...$.
Note: Before solving these types of division, first we have to check whether the given divisor is completely dividing the dividend or not. If the dividend is not completely divided then it means it gives a remainder which will be non zero, and the process will be repeated again and again. But if the dividend is completely divided by divisor then the remainder will be zero and the process becomes ended after zero remainder.
Here the given integer is $250$, now the sum of $250$ is $250=2+5+0=7$ here we can see easily $7$ is not divisible by $3$. So we will not get an integer result when dividing $250$ by $3$. So to solve this we will use a long division method.
Complete step by step answer:
In mathematics, long division is a method used for dividing larger numbers into groups or parts. Long division helps in breaking the division problem into a sequence of easier steps. Just like all division problems, a large number is divided by another number which is called the divisor, and the result called the quotient and sometimes remainder also left.
Here we have to divide $250$ by $3$, using long division method
Here $3$ is divisor and $250$ is dividend, then by long division method.
The steps which we have to follow are:
1 Divide the tens column dividend by the divisor.
2 Multiply the divisor by the quotient in the tens place column.
3 Subtract the product from the divisor.
4 Bring down the dividend in the ones column and repeat.
$\begin{align}
& 3\overset{83.333}{\overline{\left){250.000}\right.}} \\
& -24 \\
& \_\_\_\_ \\
& \,\,\,\, 10 \\
& \,\,-9 \\
& \_\_\_\_\_ \\
& \,\,\,\,\,\,\,10 \\
& \,\,\,\,\,-9 \\
& \_\_\_\_\_\_\_ \\
& \,\,\,\,\,\,\,\,\,\,10 \\
& \,\,\,\,\,\,\,\,-9 \\
& \_\_\_\_\_\_\_\_ \\
& \,\,\,\,\,\,\,\,\,\,\,\,\,10 \\
& \,\,\,\,\,\,\,\,\,\,\,-9 \\
& \_\_\_\_\_\_\_\_\ \\
& \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,1 \\
\end{align}$
Hence, we get the remainder $1$ and the quotient is $83.333...$.
Note: Before solving these types of division, first we have to check whether the given divisor is completely dividing the dividend or not. If the dividend is not completely divided then it means it gives a remainder which will be non zero, and the process will be repeated again and again. But if the dividend is completely divided by divisor then the remainder will be zero and the process becomes ended after zero remainder.
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