Velma has exactly one week to learn all 71 Japanese hiragana characters. If she can learn at-most a dozen of them on any one day and will have time to learn only 4 of them on Friday, what is the least number of hiragana characters that Velma has to learn on Saturday?
For Velma to learn the least number of characters on Saturday, she needs to learn the maximum number on the rest of the days. Make a table of days and fill with characters learned each day to avoid any confusion.
Sun = 12
Mon = 12
Tue = 12
Wed = 12
Thu = 12
Fri = 4
Sat = ?
Total = 71
Now, try to solve yourself before looking at the complete solution.
Complete step-by-step solution:
Total number of characters to be learned = 71
Let the number of characters leaned by Velma on Saturday be x.
Number of characters learned on Friday = 4
Number of characters learned on any other day = 12 (a dozen)
Total number of such days where Velma learns 12 characters = 5
The sum of characters learned on each day should be equal to 71
Which mean that 12+12+12+12+12+4+x = 71
=> x = 71-64 = 7.
Hence, Velma needs to learn at least 7 Japanese hiragana characters on Saturday. Option (C)
1) 1 Dozen = 12 items
2) The most common mistake that one can make here is to forget Sunday. In that case you come up with the answer 19.
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