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Velma has exactly one week to learn all 71 Japanese hiragana characters. If she can learn at-most a dozen of them on any one day and will have time to learn only 4 of them on Friday, what is the least number of hiragana characters that Velma has to learn on Saturday?
A) 19
B) 11
C) 7
D) 12

Answer Verified Verified
Hint:
For Velma to learn the least number of characters on Saturday, she needs to learn the maximum number on the rest of the days. Make a table of days and fill with characters learned each day to avoid any confusion.

Sun = 12

Mon = 12

Tue = 12

Wed = 12

Thu = 12

Fri = 4

Sat = ?

Total = 71

Now, try to solve yourself before looking at the complete solution.

Complete step-by-step solution:

Total number of characters to be learned = 71
Let the number of characters leaned by Velma on Saturday be x.
Number of characters learned on Friday = 4
Number of characters learned on any other day = 12 (a dozen)

Total number of such days where Velma learns 12 characters = 5

The sum of characters learned on each day should be equal to 71
Which mean that 12+12+12+12+12+4+x = 71
=> 64+x=71
=> x = 71-64 = 7.

Hence, Velma needs to learn at least 7 Japanese hiragana characters on Saturday. Option (C)


NOTE:
1) 1 Dozen = 12 items
2) The most common mistake that one can make here is to forget Sunday. In that case you come up with the answer 19.
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