
When the value of the azimuthal quantum number is 3, the maximum and the minimum values of the spin multiplicities are:
A. 4, 3
B. 8, 1
C. 1, 3
D. 8, 2
Answer
570.9k+ views
Hint: By using Azimuthal quantum number it is easy to find the orbital angular momentum and shape of the orbital. The Azimuthal quantum number is going to be denoted with a symbol l.
l value for s, p, d and f orbitals are 0, 1, 2 and 3 respectively.
There is a formula to calculate the spin multiplicity and it is as follows.
Spin multiplicity = 2S+1, here S = spin of the all electrons present in the orbital.
Complete step by step answer:
- In the question it is given that azimuthal quantum number is 3 and we have to find the maximum and minimum value of the multiplicities.
- We know that l value is 3 for f-orbital.
- The maximum number of unpaired electrons that can be accommodated in f-orbital are 7.
- Therefore for 7 electrons the spin quantum number S = $(7\times \dfrac{1}{2})=\dfrac{7}{2}$
- Thus the maximum spin multiplicity is as follows.
\[\begin{align}
& =2S+1 \\
& =2\times \dfrac{7}{2}+1 \\
& =7+1 \\
& =8 \\
\end{align}\]
- Therefore the maximum spin multiplicity if f-orbital is 8.
- Now we have to calculate the minimum multiplicity of f-orbital.
- The minimum number of unpaired electrons that can be accommodated in f-orbital is one.
- Therefore for 1 electron the spin quantum number S = $(1\times \dfrac{1}{2})=\dfrac{1}{2}$
- Thus the minimum spin multiplicity is as follows
\[\begin{align}
& =2S+1 \\
& =2\times \dfrac{1}{2}+1 \\
& =2 \\
\end{align}\]
- Therefore the maximum and minimum multiplicity of f- orbital is 8 and 2.
- So, the correct option is D.
Note: Maximum multiplicity can be calculated by taking the maximum number of unpaired electrons that can accommodate the respective orbital and the minimum multiplicity can be calculated by taking the minimum number of unpaired electrons that can accommodate the respective orbital.
For s- orbital, the maximum number of unpaired electrons is 1 and minimum number of unpaired electrons also 1.
For p- orbital, the maximum number of unpaired electrons is 3 and minimum number of unpaired electrons also 1.
For d- orbital, the maximum number of unpaired electrons is 5 and minimum number of unpaired electrons is also 1.
For f- orbital, the maximum number of unpaired electrons is 7 and minimum number of unpaired electrons also 1.
l value for s, p, d and f orbitals are 0, 1, 2 and 3 respectively.
There is a formula to calculate the spin multiplicity and it is as follows.
Spin multiplicity = 2S+1, here S = spin of the all electrons present in the orbital.
Complete step by step answer:
- In the question it is given that azimuthal quantum number is 3 and we have to find the maximum and minimum value of the multiplicities.
- We know that l value is 3 for f-orbital.
- The maximum number of unpaired electrons that can be accommodated in f-orbital are 7.
- Therefore for 7 electrons the spin quantum number S = $(7\times \dfrac{1}{2})=\dfrac{7}{2}$
- Thus the maximum spin multiplicity is as follows.
\[\begin{align}
& =2S+1 \\
& =2\times \dfrac{7}{2}+1 \\
& =7+1 \\
& =8 \\
\end{align}\]
- Therefore the maximum spin multiplicity if f-orbital is 8.
- Now we have to calculate the minimum multiplicity of f-orbital.
- The minimum number of unpaired electrons that can be accommodated in f-orbital is one.
- Therefore for 1 electron the spin quantum number S = $(1\times \dfrac{1}{2})=\dfrac{1}{2}$
- Thus the minimum spin multiplicity is as follows
\[\begin{align}
& =2S+1 \\
& =2\times \dfrac{1}{2}+1 \\
& =2 \\
\end{align}\]
- Therefore the maximum and minimum multiplicity of f- orbital is 8 and 2.
- So, the correct option is D.
Note: Maximum multiplicity can be calculated by taking the maximum number of unpaired electrons that can accommodate the respective orbital and the minimum multiplicity can be calculated by taking the minimum number of unpaired electrons that can accommodate the respective orbital.
For s- orbital, the maximum number of unpaired electrons is 1 and minimum number of unpaired electrons also 1.
For p- orbital, the maximum number of unpaired electrons is 3 and minimum number of unpaired electrons also 1.
For d- orbital, the maximum number of unpaired electrons is 5 and minimum number of unpaired electrons is also 1.
For f- orbital, the maximum number of unpaired electrons is 7 and minimum number of unpaired electrons also 1.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

