Question

Valency of $Cr$ in $CrP{O_4}$ is:
(A). \[4\]
(B) $3$
(C) $2$
(D) $1$

Answer 1

Hint:Valency is the measure of the combining capacity of atoms on molecules. Therefore, it is the capacity of an atom of a single element to react and combine with a particular number of atoms of another element.

Complete step by step answer:
We know that, $CrP{O_4} \to C{r^{3 + }} + PO_4^{3 - }$
$PO_4^{3 - }$ ion is having the valency of $3$.
$x - 3 = 0$
$x = 3$
Is the valency of $Cr$ in $CrP{O_4}$.
Hence, $3$ is the answer.

Additional information:
Phosphate $\left( {{3^ - }} \right)$ is an ion that is the conjugate base of hydrogen phosphate.
It is phosphate ion and a trivalent inorganic anion. It is the conjugate base of hydrogen phosphate.

$PO_4^{3 - }$ can contribute buffering strength, sequestering power, dispersion and absorptive capabilities and solubilities.
Chromium phosphate is also used to catalyze cation exchange in sorption reaction. This catalysis is widely used in the reduction of metal toxicity during environmental clean ups. This had been applied in decreasing the concentration of lead in aquatic habitat and drinking water.
Chromium is a member of group $6$ of transition metals. The $ + 3$ and $ + 6$ occur the most commonly within chromium compounds.

Note:
 High phosphate levels in the human body could lead to kidney disease, intestinal inflammation, decreased bone density, heart conditions and even premature death.