
How do you use the midpoint formula to find an endpoint?
Answer
545.4k+ views
Hint: Here, the midpoint formula is used to find the other endpoint if one end point and a midpoint is given. If we assume one endpoint as $\left( {{x}_{1}},{{y}_{1}} \right)$, midpoint as (a, b) and other endpoint as $\left( {{x}_{2}},{{y}_{2}} \right)$, then by using midpoint formula we can find the midpoint of a straight line using two endpoints.
Midpoint formula is:
$\Rightarrow \left( a,b \right)=\left[ \left( \dfrac{{{x}_{1}}+{{x}_{2}}}{2} \right),\left( \dfrac{{{y}_{1}}+{{y}_{2}}}{2} \right) \right]$
Where ‘a’ and ‘b’ are coordinates of midpoint, ${{x}_{1}}$ and ${{x}_{2}}$ are coordinates of x-axis and, ${{y}_{1}}$ and ${{y}_{2}}$ are coordinates of y-axis.
Complete step by step answer:
Let’s discuss the question now.
If we are given a straight line having two end points and there is one midpoint of that line, we can find the midpoint of that line by using the midpoint formula.
From the figure, let’s understand the concept of midpoint. Here, 2 endpoints $\left( {{x}_{1}},{{y}_{1}} \right)$ and $\left( {{x}_{2}},{{y}_{2}} \right)$ are given. The midpoint of the line is (a, b). So the formula for obtaining the midpoint is:
$\Rightarrow \left( a,b \right)=\left[ \left( \dfrac{{{x}_{1}}+{{x}_{2}}}{2} \right),\left( \dfrac{{{y}_{1}}+{{y}_{2}}}{2} \right) \right]$
But as per question, it is said that if we are given one of the end point and the midpoint then how we have to obtain the other end point. Let’s say that $\left( {{x}_{1}},{{y}_{1}} \right)$ and (a, b) is given but we need to find $\left( {{x}_{2}},{{y}_{2}} \right)$. For that we will obtain the equation from given coordinates.
There are two coordinates of midpoint i.e. a and b. To find ${{x}_{2}}$, we will use ‘a’ coordinate:
$\Rightarrow a=\dfrac{{{x}_{1}}+{{x}_{2}}}{2}$
Now, 2 will get multiplied by ‘a’:
$\Rightarrow 2a={{x}_{1}}+{{x}_{2}}$
Find ${{x}_{2}}$:
$\Rightarrow 2a-{{x}_{1}}={{x}_{2}}$
Similarly for ${{y}_{2}}$, we will use ‘b’ coordinate:
$\Rightarrow b=\dfrac{{{y}_{1}}+{{y}_{2}}}{2}$
Now, 2 will get multiplied by ‘b’:
$\Rightarrow 2b={{y}_{1}}+{{y}_{2}}$
Find ${{y}_{2}}$:
$\Rightarrow 2b-{{y}_{1}}={{y}_{2}}$
So, for finding $\left( {{x}_{2}},{{y}_{2}} \right)$, we will use the following equations:
$\Rightarrow 2a-{{x}_{1}}={{x}_{2}}$
$\Rightarrow 2b-{{y}_{1}}={{y}_{2}}$
This is the final answer.
Note: Midpoint formula is not only used for straight lines but also used for finding the midpoints of the length of the triangles. Any one of the end points can be obtained by applying the formulae taken out in the final step above. The midpoints can be found just by taking the average of two coordinates of each axis.
Midpoint formula is:
$\Rightarrow \left( a,b \right)=\left[ \left( \dfrac{{{x}_{1}}+{{x}_{2}}}{2} \right),\left( \dfrac{{{y}_{1}}+{{y}_{2}}}{2} \right) \right]$
Where ‘a’ and ‘b’ are coordinates of midpoint, ${{x}_{1}}$ and ${{x}_{2}}$ are coordinates of x-axis and, ${{y}_{1}}$ and ${{y}_{2}}$ are coordinates of y-axis.
Complete step by step answer:
Let’s discuss the question now.
If we are given a straight line having two end points and there is one midpoint of that line, we can find the midpoint of that line by using the midpoint formula.
From the figure, let’s understand the concept of midpoint. Here, 2 endpoints $\left( {{x}_{1}},{{y}_{1}} \right)$ and $\left( {{x}_{2}},{{y}_{2}} \right)$ are given. The midpoint of the line is (a, b). So the formula for obtaining the midpoint is:
$\Rightarrow \left( a,b \right)=\left[ \left( \dfrac{{{x}_{1}}+{{x}_{2}}}{2} \right),\left( \dfrac{{{y}_{1}}+{{y}_{2}}}{2} \right) \right]$
But as per question, it is said that if we are given one of the end point and the midpoint then how we have to obtain the other end point. Let’s say that $\left( {{x}_{1}},{{y}_{1}} \right)$ and (a, b) is given but we need to find $\left( {{x}_{2}},{{y}_{2}} \right)$. For that we will obtain the equation from given coordinates.
There are two coordinates of midpoint i.e. a and b. To find ${{x}_{2}}$, we will use ‘a’ coordinate:
$\Rightarrow a=\dfrac{{{x}_{1}}+{{x}_{2}}}{2}$
Now, 2 will get multiplied by ‘a’:
$\Rightarrow 2a={{x}_{1}}+{{x}_{2}}$
Find ${{x}_{2}}$:
$\Rightarrow 2a-{{x}_{1}}={{x}_{2}}$
Similarly for ${{y}_{2}}$, we will use ‘b’ coordinate:
$\Rightarrow b=\dfrac{{{y}_{1}}+{{y}_{2}}}{2}$
Now, 2 will get multiplied by ‘b’:
$\Rightarrow 2b={{y}_{1}}+{{y}_{2}}$
Find ${{y}_{2}}$:
$\Rightarrow 2b-{{y}_{1}}={{y}_{2}}$
So, for finding $\left( {{x}_{2}},{{y}_{2}} \right)$, we will use the following equations:
$\Rightarrow 2a-{{x}_{1}}={{x}_{2}}$
$\Rightarrow 2b-{{y}_{1}}={{y}_{2}}$
This is the final answer.
Note: Midpoint formula is not only used for straight lines but also used for finding the midpoints of the length of the triangles. Any one of the end points can be obtained by applying the formulae taken out in the final step above. The midpoints can be found just by taking the average of two coordinates of each axis.
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