
How do you use the law of exponents to simplify the expression $ {\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} $
Answer
441.3k+ views
Hint: As you can see in the question the bases are the same but the powers are different which indicate to us that we have to use the laws of indices. But the expression will not be simplified using any one law of indices. You will have to use various different laws of indices as required. Start the process within the bracket first.
Complete step-by-step answer:
The expression that is given above looks scary but can be broken down if proper laws are applied.
Looking at the question first thing you can spot is that the bases are the same and their powers are differing which is a good sign as we know that when the bases are same and the powers differ it’s time to use the laws of indices.
Since there are multiple indices present first we will try to sort things within the bracket.
We are going to use $ \dfrac{1}{{{a^n}}} = {a^{ - n}} $
Hence the above expression will become
$ {\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} $ = $ {\left( {{3^2}{{.3}^3}} \right)^{\dfrac{3}{5}}} $
Now using $ {a^m}.{a^n} = {a^{m + n}} $ we get
\[{\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} = {\left( {{3^{2 + 3}}} \right)^{\dfrac{3}{5}}}\]
$ \Rightarrow {\left( {{3^5}} \right)^{\dfrac{3}{5}}} $
Now using $ {\left( {{a^n}} \right)^m} = {a^{n \times m}} $ , we get
\[{\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} = {3^{5 \times \dfrac{3}{5}}}\]
which solving further we get
\[{\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} = {3^3} = 27\]
hence this is the final value of the above equation.\[{\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} = {3^3} = 27\]
So, the correct answer is “27”.
Note: State the law first and then apply it. Identification of laws to be used in this kind of expression is utmost necessary. As this will decide whether the expression will get simplified or not. Also the laws should be applied in order while solving the expression as this can lead to many mathematical errors.
Complete step-by-step answer:
The expression that is given above looks scary but can be broken down if proper laws are applied.
Looking at the question first thing you can spot is that the bases are the same and their powers are differing which is a good sign as we know that when the bases are same and the powers differ it’s time to use the laws of indices.
Since there are multiple indices present first we will try to sort things within the bracket.
We are going to use $ \dfrac{1}{{{a^n}}} = {a^{ - n}} $
Hence the above expression will become
$ {\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} $ = $ {\left( {{3^2}{{.3}^3}} \right)^{\dfrac{3}{5}}} $
Now using $ {a^m}.{a^n} = {a^{m + n}} $ we get
\[{\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} = {\left( {{3^{2 + 3}}} \right)^{\dfrac{3}{5}}}\]
$ \Rightarrow {\left( {{3^5}} \right)^{\dfrac{3}{5}}} $
Now using $ {\left( {{a^n}} \right)^m} = {a^{n \times m}} $ , we get
\[{\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} = {3^{5 \times \dfrac{3}{5}}}\]
which solving further we get
\[{\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} = {3^3} = 27\]
hence this is the final value of the above equation.\[{\left( {\dfrac{{{3^2}}}{{{3^{ - 3}}}}} \right)^{\dfrac{3}{5}}} = {3^3} = 27\]
So, the correct answer is “27”.
Note: State the law first and then apply it. Identification of laws to be used in this kind of expression is utmost necessary. As this will decide whether the expression will get simplified or not. Also the laws should be applied in order while solving the expression as this can lead to many mathematical errors.
Recently Updated Pages
The correct geometry and hybridization for XeF4 are class 11 chemistry CBSE

Water softening by Clarks process uses ACalcium bicarbonate class 11 chemistry CBSE

With reference to graphite and diamond which of the class 11 chemistry CBSE

A certain household has consumed 250 units of energy class 11 physics CBSE

The lightest metal known is A beryllium B lithium C class 11 chemistry CBSE

What is the formula mass of the iodine molecule class 11 chemistry CBSE

Trending doubts
When Sambhaji Maharaj died a 11 February 1689 b 11 class 8 social science CBSE

Write the smallest number divisible by both 306 and class 8 maths CBSE

In Indian rupees 1 trillion is equal to how many c class 8 maths CBSE

Contrast the Chinese view of art with the European class 8 social science CBSE

What is 1 divided by 0 class 8 maths CBSE

A circle can have parallel tangents at the most class 8 maths CBSE
