Question

Upon heating \[{\rm{KCl}}{{\rm{O}}_{\rm{3}}}\] in the presence of catalysis amount of \[{\rm{Mn}}{{\rm{O}}_{\rm{2}}}\], a gas is formed \[{\rm{W}}\] is formed . Excess amount of \[{\rm{W}}\] reacts with white phosphorus to give \[{\rm{X}}\]. The reaction of \[{\rm{X}}\] with \[{\rm{HN}}{{\rm{O}}_{\rm{3}}}\] gives \[{\rm{Y}}\]and \[{\rm{Z}}\]. \[{\rm{W}}\] and \[{\rm{X}}\] are, respectively
(A) \[{{\rm{O}}_2}\]and \[{{\rm{P}}_4}{{\rm{O}}_{10}}\]
(B) \[{{\rm{O}}_2}\]and \[{{\rm{P}}_4}{{\rm{O}}_6}\]
(C) \[{{\rm{O}}_3}\]and \[{{\rm{P}}_4}{{\rm{O}}_6}\]
(D) \[{{\rm{O}}_3}\]and \[{{\rm{P}}_4}{{\rm{O}}_{10}}\]

Answer 1

Hint: As we know that \[{\rm{KCl}}{{\rm{O}}_{\rm{3}}}\]when heated it release a gas which is diatomic. Phosphorus reacts very fast with this gas and forms a compound which is very shiny in the dark. It is also found where the human body burns.

Complete step by step answer
When \[{\rm{KCl}}{{\rm{O}}_{\rm{3}}}\] is heated in the presence of catalyst it releases oxygen gas as
\[{\rm{2}}\,{\rm{KCl}}{{\rm{O}}_{\rm{3}}} \to \,{\rm{2}}\,{\rm{KCl + }}\,{\rm{3}}\,{{\rm{O}}_{\rm{2}}}{\rm{(g)}}\]
So, \[{\rm{W}}\] is oxygen gas.
When an excess amount of oxygen gas reacts with white phosphorus, it gives a compound whose name is phosphorus penta-oxide. The reaction occurs as-
\[{{\rm{P}}_{\rm{4}}}{\rm{(white}}\,{\rm{phosphorous) + }}\,{\rm{5}}{{\rm{O}}_{\rm{2}}} \to \,{{\rm{P}}_{\rm{4}}}{{\rm{O}}_{{\rm{10}}}}{\rm{(Phosphorous}}\,{\rm{pentaoxide)}}\]
phosphorus penta-oxide is a compound which is the oxidized form of phosphorus, so when the human body burns phosphorus it reacts with oxygen, so due to oxidation of phosphorus, phosphorus penta-oxide shines in the dark.
Therefore, \[{\rm{X}}\] is \[{{\rm{P}}_{\rm{4}}}{{\rm{O}}_{{\rm{10}}}}\].
Now, \[{\rm{X}}\] reacts with \[{\rm{HN}}{{\rm{O}}_{\rm{3}}}\], it gives as
\[{{\rm{P}}_{\rm{4}}}{{\rm{O}}_{{\rm{10}}}}\,{\rm{ + }}\,{\rm{HN}}{{\rm{O}}_{\rm{3}}} \to {{\rm{N}}_{\rm{2}}}{{\rm{O}}_{\rm{5}}}{\rm{ + }}\,{\rm{HP}}{{\rm{O}}_{\rm{3}}}\]
Where \[{{\rm{N}}_{\rm{2}}}{{\rm{O}}_{\rm{5}}}\] is \[{\rm{Y}}\] and \[{\rm{HP}}{{\rm{O}}_{\rm{3}}}\] is \[{\rm{Z}}\]. Both \[{\rm{Y}}\] and \[{\rm{Z}}\] are known as nitrogen-pentoxide and metaphosphoric acid respectively. \[{\rm{Y}}\] is also known as oxide of nitrogen and \[{\rm{Z}}\] is known as oxoacid of phosphorus.

Therefore, our correct option is option(A).

Note:
When any atom reacts with oxygen then it is known as oxidation, in the oxidation process atom loses its electrons because oxygen is a second most electronegative atom in periodic table after fluorine. We can calculate that an atom loses how many electrons from its outermost shell by calculating oxidation number.