Question

# What is the unit of electric field intensity?${\text{A}}{\text{.}}$ Newton per metre ${\text{B}}{\text{.}}$ Coulomb per newton${\text{C}}{\text{.}}$ Newton per coulomb${\text{D}}{\text{.}}$ Joule per newton

Electric charge is carried by the subatomic particles of an atom such as electrons and photons. The charge of an electron is about $1.6 \times {10^{ - 19}}$ coulombs. Every charged particle creates a space around it in which the effect of its electric force is felt. This space around the charged particles is known as the “Electric field“. Whenever a unit test charge is placed in this electric field it will experience the force emitted by the source particle. The amount of force experienced by a unit charged particle when it is placed in the electric field is known as Electric field intensity.
Electric field intensity = $\dfrac{{{\text{Force experienced}}}}{{{\text{Magnitude of the charge}}}}$ i.e., E = $\dfrac{{\text{F}}}{{\text{q}}}$
Note- Since, the S.I units of force is newton and the S.I unit of charge magnitude is coulomb that’s why the S.I units of electric field intensity E = $\dfrac{{\text{F}}}{{\text{q}}}$ will be newton per coulomb. Also, note that electric field intensity is a vector quantity that means it will possess both magnitude as well as direction.