
What do you understand by sex-linked characters? A normal man marries either a colour blind or a carrier woman. Predict the kind of children which may be expected in both the conditions.
Answer
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Hint:A character refers to a genetically controlled observable trait or property of an organism. When sex chromosomes are involved, the character becomes sex-linked.
Complete solution:If the presence of X or Y chromosome (sex-chromosomes) determine the expression of a character, then it is called a sex-linked character. An example of a sex-linked disease is colour blindness. It is an X-linked disease. A person would be colour blind if he/she has a defective X chromosome.
Considering, \[{X^c}\] as the defective X chromosome responsible for colour blindness.
Then, the genotype of a normal man: XY (no defective X)
The genotype of a colour blind woman: \[{X^c}{X^c}\]
The genotype of a carrier woman: \[X{X^c}\]
Case I: A normal man (XY) marries a colour blind woman \[\left( {{X^c}{X^c}} \right)\].
In this case, all the sons and daughters would get colour blindness.
The case I: A normal man (XY) marries a carrier woman (XXc).
In this case, \[50\% \] daughters would be normal; others \[50\% \] would be carriers. Among sons, \[50\% \] would be normal and the rest would have colour-blindness.
Note: Colour blindness is a recessive X-linked disease. Presence of the gene in a single X chromosome of females makes them a carrier for the disease. As males have only one X chromosome and if it has the concerned gene then the male would be affected.
Complete solution:If the presence of X or Y chromosome (sex-chromosomes) determine the expression of a character, then it is called a sex-linked character. An example of a sex-linked disease is colour blindness. It is an X-linked disease. A person would be colour blind if he/she has a defective X chromosome.
Considering, \[{X^c}\] as the defective X chromosome responsible for colour blindness.
Then, the genotype of a normal man: XY (no defective X)
The genotype of a colour blind woman: \[{X^c}{X^c}\]
The genotype of a carrier woman: \[X{X^c}\]
Case I: A normal man (XY) marries a colour blind woman \[\left( {{X^c}{X^c}} \right)\].
| Gametes | Xc | Xc |
| X | XcXc(colour blind daughter) | XcXc(colour blind daughter) |
| Y | XcY(colour blind son) | XcY(colour blind son) |
In this case, all the sons and daughters would get colour blindness.
The case I: A normal man (XY) marries a carrier woman (XXc).
| Gametes | X | Xc |
| X | XX(normal daughter) | XXc(carrier daughter) |
| Y | XY(normal son) | XcY(colour blind son |
In this case, \[50\% \] daughters would be normal; others \[50\% \] would be carriers. Among sons, \[50\% \] would be normal and the rest would have colour-blindness.
Note: Colour blindness is a recessive X-linked disease. Presence of the gene in a single X chromosome of females makes them a carrier for the disease. As males have only one X chromosome and if it has the concerned gene then the male would be affected.
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