Question

What type of bond does the compound $Pb{{({{C}_{2}}{{H}_{3}}{{O}_{2}})}_{2}}$ have?

Answer 1

Hint: To find the type of the bonds we should know what types of elements are present in the given chemical compound. We have to find the type of bond that is present based on the metallic and nonmetallic character of the elements present in the given chemical.

Complete answer:
- In the question it is asked to find the type of bond present in the given compound $Pb{{({{C}_{2}}{{H}_{3}}{{O}_{2}})}_{2}}$ .
- We know that the chemical name of the given compound $Pb{{({{C}_{2}}{{H}_{3}}{{O}_{2}})}_{2}}$ is lead (II) acetate.
- We already know that the chemical name of the ionic compound can be written as Metal (charge) anion.
- In the name of the compound lead (II) acetate, we can see that there is a metal lead and the anion is acetate.
- Therefore the bond which is present in between the lead and acetate in the given chemical $Pb{{({{C}_{2}}{{H}_{3}}{{O}_{2}})}_{2}}$ is ionic.
- Because lead is a metal and acetate is an anion.
- Now coming to the bonds in the acetate anion itself.
- The bonds which are present in the carbon-carbon, carbon-hydrogen and carbon-oxygen of the acetate anion are covalent in nature.
- The covalent nature of the carbon-carbon, carbon-hydrogen and carbon-oxygen bonds is due to the less difference in the electronegative values of the respective atoms.

Note:
We can write the reaction of lead with acetate and it is as follows.
\[P{{b}^{2+}}+2{{({{C}_{2}}{{H}_{3}}{{O}_{2}})}^{-}}\to Pb{{({{C}_{2}}{{H}_{3}}{{O}_{2}})}_{2}}\]
In the above chemical reaction we can see that one moles of lead cation is going to react with two moles of acetate and forms one mole of lead acetate as the product.