
Two monatomic ideal gas at temperature and are mixed. There is no loss of energy. If the masses of molecules of the gases are and and the number of their molecules are and respectively. The temperature of the mixture will be:
A.
B.
C.
D.
Answer
458.4k+ views
Hint: Use the formula for internal energy and find the internal energy at temperature and then at . As there is no loss of energy, the sum of change of internal energies must be zero. Substitute the values in the mentioned expression. Now, substitute the value for internal energy of gas at constant volume. Then, consider T as the final temperature of the mixture, substitute it in the above obtained expression. Rearrange the equation and obtain the temperature of the mixture.
Formula used:
Complete answer:
It is given that there is no loss of energy which means that the sum of change of internal energies must be zero. Mathematically this can be written as,
…(1)
Where, is the internal energy at temperature
is the internal energy at temperature
We know, internal energy is given by,
Where, n is the number of molecules
is the internal energy of gas at constant volume
Using above equation we can write the internal energy at temperature as,
…(2)
Similarly, we can write the internal energy at temperature as,
…(2)
Substituting equation. (2) and (3) in equation. (1) we get,
…(4)
We know, for monoatomic gases,
It is given that both the gases are monatomic. Thus,
Substituting this value in the equation. (4) we get,
…(5)
Let the final temperature be T.
Thus, equation. (5) can be written as,
Rearranging the above equation we get,
Thus, the temperature of the mixture will be .
So, the correct answer is option D i.e. .
Note:
To solve these types of questions, students must have the clear understanding of thermodynamics and its laws. Also, they should know the ideal gas law and how varying the different parameters changes the behaviour of gases at various conditions.
Formula used:
Complete answer:
It is given that there is no loss of energy which means that the sum of change of internal energies must be zero. Mathematically this can be written as,
Where,
We know, internal energy is given by,
Where, n is the number of molecules
Using above equation we can write the internal energy at temperature
Similarly, we can write the internal energy at temperature
Substituting equation. (2) and (3) in equation. (1) we get,
We know, for monoatomic gases,
It is given that both the gases are monatomic. Thus,
Substituting this value in the equation. (4) we get,
Let the final temperature be T.
Thus, equation. (5) can be written as,
Rearranging the above equation we get,
Thus, the temperature of the mixture will be
So, the correct answer is option D i.e.
Note:
To solve these types of questions, students must have the clear understanding of thermodynamics and its laws. Also, they should know the ideal gas law and how varying the different parameters changes the behaviour of gases at various conditions.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Trending doubts
Father of Indian ecology is a Prof R Misra b GS Puri class 12 biology CBSE

Who is considered as the Father of Ecology in India class 12 biology CBSE

Enzymes with heme as prosthetic group are a Catalase class 12 biology CBSE

A deep narrow valley with steep sides formed as a result class 12 biology CBSE

An example of ex situ conservation is a Sacred grove class 12 biology CBSE

Why is insulin not administered orally to a diabetic class 12 biology CBSE
