
Two equal forces \[\overrightarrow{F}\] each act at a right angles to each other. The third force which can neutralize their effect is:
\[\begin{align}
& \text{A) }\sqrt{2}F\text{,in the same plane of two forces}\text{.} \\
& \text{B) }\sqrt{2}F\text{,in the different plane of the two forces}\text{.} \\
& \text{C) 2}F\text{,in the same plane of two forces}\text{.} \\
& \text{D) 2}F\text{,in the different plane of two forces}\text{.} \\
\end{align}\]
Answer
571.5k+ views
Hint: We have been given that two equal forces act at the right angle to each other and we have to find the third force which can neutralize their effect on each other. First, we will draw a simple diagram and then discuss the given situation and find the answer to it. From the option, we can say that we have to find answers in terms of F.
Complete step-by-step solution
Let us draw a simple diagram for the given question.
Here we can see there are two forces of magnitude F which are acted at right angles to each other. The force F’ is the resultant force, and this resultant force will neutralize the effect of both forces having magnitude F.
Now the resultant force F’ can be given by addition of vectors, hence we can write
\[\begin{align}
& F'=\sqrt{{{\left( F \right)}^{2}}+{{\left( F \right)}^{2}}} \\
& \Rightarrow F'=\sqrt{2{{F}^{2}}} \\
& \Rightarrow F'=\sqrt{2}F \\
\end{align}\]
Now as the force are acted at right angles therefore the resultant force will be acting in the same plane as the plane of two forces.
Hence the magnitude of the force, which can neutralize the effect of F is \[\sqrt{2}F\], in the same plane of the two forces.
Hence option A is the correct answer.
Note: The force is a vector quantity, which has both directions as well as magnitude. Therefore, here we have used the addition of vectors to find the resultant force. As mentioned above \[\sqrt{2}F\]is the magnitude and it does not give the direction in which the force is acted. Note that these forces are not acting on each other it is acted on somebody.
Complete step-by-step solution
Let us draw a simple diagram for the given question.
Here we can see there are two forces of magnitude F which are acted at right angles to each other. The force F’ is the resultant force, and this resultant force will neutralize the effect of both forces having magnitude F.
Now the resultant force F’ can be given by addition of vectors, hence we can write
\[\begin{align}
& F'=\sqrt{{{\left( F \right)}^{2}}+{{\left( F \right)}^{2}}} \\
& \Rightarrow F'=\sqrt{2{{F}^{2}}} \\
& \Rightarrow F'=\sqrt{2}F \\
\end{align}\]
Now as the force are acted at right angles therefore the resultant force will be acting in the same plane as the plane of two forces.
Hence the magnitude of the force, which can neutralize the effect of F is \[\sqrt{2}F\], in the same plane of the two forces.
Hence option A is the correct answer.
Note: The force is a vector quantity, which has both directions as well as magnitude. Therefore, here we have used the addition of vectors to find the resultant force. As mentioned above \[\sqrt{2}F\]is the magnitude and it does not give the direction in which the force is acted. Note that these forces are not acting on each other it is acted on somebody.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

