Train fare between Patna to Munger for one adult is three times the train fare of one child. If the adult fare is 102, then what will be the fare of 2 adults and 3 children together for the same distance?
(a) 306
(b) 212
(c) 206
(d) 214
Answer
613.2k+ views
Hint: We start solving the problem by finding the fare for one child using the information that the adult fare is three times the fare of one child. We then use this child fare and the given adult fare for calculating the fare of 2 adults and 3 children together travelling from Patna to Munger.
Complete step by step answer:
According to the problem, we are given that the train fare between Patna to Munger for one adult is three times the train fare of one child. We need to find the fare of 2 adults and 3 children together travelling from Patna to Munger if the adult fare is 102.
Let us first find the fare for one child. We have given that the adult fare is three times the fare of one child.
So, we get 3\[\times \] Child fare = 102.
$\Rightarrow $ Child fare = $\dfrac{102}{3}$.
$\Rightarrow $ Child fare = 34 ---(1).
Now, let us find the fare for 2 adults and 3 children.
So, we get the total fare as $\left( 2\times 102 \right)+\left( 3\times 34 \right)=204+102=306$.
So, we have found the fare for 2 adults and 3 children as 306.
So, the correct answer is “Option a”.
Note: We can also solve this problem by assuming 3 children as 1 adult which will also give us the same answer. We should not make calculation mistakes while performing division, multiplication and addition operations in this problem. Whenever we get this type of problem, we try to solve for the values of all unknowns present which will help us to get the required solution.
Complete step by step answer:
According to the problem, we are given that the train fare between Patna to Munger for one adult is three times the train fare of one child. We need to find the fare of 2 adults and 3 children together travelling from Patna to Munger if the adult fare is 102.
Let us first find the fare for one child. We have given that the adult fare is three times the fare of one child.
So, we get 3\[\times \] Child fare = 102.
$\Rightarrow $ Child fare = $\dfrac{102}{3}$.
$\Rightarrow $ Child fare = 34 ---(1).
Now, let us find the fare for 2 adults and 3 children.
So, we get the total fare as $\left( 2\times 102 \right)+\left( 3\times 34 \right)=204+102=306$.
So, we have found the fare for 2 adults and 3 children as 306.
So, the correct answer is “Option a”.
Note: We can also solve this problem by assuming 3 children as 1 adult which will also give us the same answer. We should not make calculation mistakes while performing division, multiplication and addition operations in this problem. Whenever we get this type of problem, we try to solve for the values of all unknowns present which will help us to get the required solution.
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