
What is total resistance , between A and B in the circuit shown in the figure.
A. $1\Omega$
B. $0.5\Omega$
C. $2\Omega$
D. $3\Omega$
Answer
541.8k+ views
Hint: Clearly, the given figure consists of a combination of resistances which are connected in parallel and series with each other. In a series connection, we know that the flow of current through the circuit is a constant . While in parallel circuit, we know that the flow of voltage through the circuit is a constant. Using the formula, we can find the total resistance.
Formula used:
$R_{s}=R_{1}+R_{2}$ and $\dfrac{1}{R_{p}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}$
Complete step-by-step answer:
We know that Ohm’s law gives the relationship between voltage $V$, current $I$ and resistance $R$. It is given as $V=IR$ at constant temperature .
We also know that, since current in the series connection is constant or same amount of current flows through the circuit , then the effective resistance $R_{s}$is given by $R_{s}=R_{1}+R_{2}$
Also, since voltage in the parallel connection is constant same amount of voltage flows through the circuit , then the effective resistance $R_{p}$ I given by $\dfrac{1}{R_{p}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}$
Clearly from the above figure, AB is in series with BC, then we have,
$R=4+2=6\Omega$
Again, ABC is in parallel with AC,
$\dfrac{1}{R}=\dfrac{1}{4}+\dfrac{1}{6}=\dfrac{3}{12}+\dfrac{2}{12}=\dfrac{5}{12}$
$\implies R=\dfrac{12}{5}$
This new AC is in series with CD
$R=\dfrac{12}{5}+2=\dfrac{12+10}{5}=\dfrac{22}{5}$
Again, ACD is in parallel with AD,
$\dfrac{1}{R}=\dfrac{5}{22}+\dfrac{1}{4}=\dfrac{20+22}{88}=\dfrac{44}{88}=\dfrac{1}{2}$
$\implies R=2$
Again, AD is in series with DE
$R=2+2=4$
Again ADE is in parallel with AE
$\dfrac{1}{R}=\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{1}{2}$
$\implies R=2$
Again AE is in series with EF
$R=2+2=4$
AEF is in parallel with AF
$\dfrac{1}{R}=\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{2}{4}=\dfrac{1}{2}$
$\implies R=2$
So, the correct answer is “Option C”.
Note: Since it is not possible, every time to calculate the current or voltage passing through the circuit. Another, easy way to identify if the resistances are in series or parallel connections is by observing the circuit diagram. If two or more resistances have a pair of common points then, then they are said to be in parallel circuit. If two or more resistances have less than two or only one common point then, they are said to be in series circuit.
Formula used:
$R_{s}=R_{1}+R_{2}$ and $\dfrac{1}{R_{p}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}$
Complete step-by-step answer:
We know that Ohm’s law gives the relationship between voltage $V$, current $I$ and resistance $R$. It is given as $V=IR$ at constant temperature .
We also know that, since current in the series connection is constant or same amount of current flows through the circuit , then the effective resistance $R_{s}$is given by $R_{s}=R_{1}+R_{2}$
Also, since voltage in the parallel connection is constant same amount of voltage flows through the circuit , then the effective resistance $R_{p}$ I given by $\dfrac{1}{R_{p}}=\dfrac{1}{R_{1}}+\dfrac{1}{R_{2}}$
Clearly from the above figure, AB is in series with BC, then we have,
$R=4+2=6\Omega$
Again, ABC is in parallel with AC,
$\dfrac{1}{R}=\dfrac{1}{4}+\dfrac{1}{6}=\dfrac{3}{12}+\dfrac{2}{12}=\dfrac{5}{12}$
$\implies R=\dfrac{12}{5}$
This new AC is in series with CD
$R=\dfrac{12}{5}+2=\dfrac{12+10}{5}=\dfrac{22}{5}$
Again, ACD is in parallel with AD,
$\dfrac{1}{R}=\dfrac{5}{22}+\dfrac{1}{4}=\dfrac{20+22}{88}=\dfrac{44}{88}=\dfrac{1}{2}$
$\implies R=2$
Again, AD is in series with DE
$R=2+2=4$
Again ADE is in parallel with AE
$\dfrac{1}{R}=\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{1}{2}$
$\implies R=2$
Again AE is in series with EF
$R=2+2=4$
AEF is in parallel with AF
$\dfrac{1}{R}=\dfrac{1}{4}+\dfrac{1}{4}=\dfrac{2}{4}=\dfrac{1}{2}$
$\implies R=2$
So, the correct answer is “Option C”.
Note: Since it is not possible, every time to calculate the current or voltage passing through the circuit. Another, easy way to identify if the resistances are in series or parallel connections is by observing the circuit diagram. If two or more resistances have a pair of common points then, then they are said to be in parallel circuit. If two or more resistances have less than two or only one common point then, they are said to be in series circuit.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

Why cannot DNA pass through cell membranes class 12 biology CBSE

Differentiate between insitu conservation and exsitu class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

