
The weight of one mango is 400gm, one guava is 200gm and musk melon is 1 kg 200 gm. Now fill this table based on this information.
Weight of 2 mangoes = Weight of ________ guavas.
Weight of 5 muskmelons = Weight of ________ mangoes.
Weight of 5 mangoes and 2 guavas = Weight of ________ musk melons.
Answer
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Hint: Find the total weight of 2 mangoes and equate it with weight of one guava multiplied by k, where k is the number of guavas having weight equal to that of two mangoes. Solve the equation to get the value of k. Similarly solve the other two parts as well. Don’t forget to convert the weight of muskmelons to a single unit, preferably grams.
Complete step-by-step answer:
Let us start the solution by letting the number of guavas having weight equal to that of 2 mangoes be k, number of mangoes having weight equal to that of 5 muskmelons be l and number of muskmelons having the same weight as of the combined weight of 5 mangoes and 2 guavas be m.
Now it is given:
Weight of one mango = 400gm.
Weight of one guava = 200gm.
Weight of one musk melon = 1kg 200gm = 1200gm.
Now let us find the weight of two mangoes, which is equal to 2 times the weight of each mango.
Weight of 2 mangoes = $2\times 400=800gm$ .
Now we will equate this with the weight of the guava multiplied by k, as the weight of k guavas is equal to the weight of 2 mangoes.
$k\times 200=800$
$\Rightarrow k=4\text{ guavas}\text{.}$
Similarly, we will equate the weight of five musk melons with the weight of the mango multiplied by l, as the weight of l mangoes is equal to the weight of 5 muskmelons.
$l\times 400=1200\times 5$
$\Rightarrow l=15\text{ mangoes}\text{.}$
Finally, we will equate the weight of 5 mangoes and 2 guavas with the weight of the musk melon multiplied by m, as the weight of m muskmelons is equal to the weight of 5 mangoes added with 2 guavas..
$m\times 1200=5\times 400+2\times 200$
$\Rightarrow m\times 1200=2400$
$\Rightarrow m=2\text{ musk melons}\text{.}$
Therefore, we can conclude that:
Weight of 2 mangoes = Weight of 4 guavas.
Weight of 5 muskmelons = Weight of 15 mangoes.
Weight of 5 mangoes and 2 guavas = Weight of 2 muskmelons.
Note: Be careful in the calculation part, as the only mistake that can be committed in the above problem is in the calculation part. Also, don’t forget to convert all the masses to a single unit system, preferably the smallest among the ones used in the question to avoid decimal calculations.
Complete step-by-step answer:
Let us start the solution by letting the number of guavas having weight equal to that of 2 mangoes be k, number of mangoes having weight equal to that of 5 muskmelons be l and number of muskmelons having the same weight as of the combined weight of 5 mangoes and 2 guavas be m.
Now it is given:
Weight of one mango = 400gm.
Weight of one guava = 200gm.
Weight of one musk melon = 1kg 200gm = 1200gm.
Now let us find the weight of two mangoes, which is equal to 2 times the weight of each mango.
Weight of 2 mangoes = $2\times 400=800gm$ .
Now we will equate this with the weight of the guava multiplied by k, as the weight of k guavas is equal to the weight of 2 mangoes.
$k\times 200=800$
$\Rightarrow k=4\text{ guavas}\text{.}$
Similarly, we will equate the weight of five musk melons with the weight of the mango multiplied by l, as the weight of l mangoes is equal to the weight of 5 muskmelons.
$l\times 400=1200\times 5$
$\Rightarrow l=15\text{ mangoes}\text{.}$
Finally, we will equate the weight of 5 mangoes and 2 guavas with the weight of the musk melon multiplied by m, as the weight of m muskmelons is equal to the weight of 5 mangoes added with 2 guavas..
$m\times 1200=5\times 400+2\times 200$
$\Rightarrow m\times 1200=2400$
$\Rightarrow m=2\text{ musk melons}\text{.}$
Therefore, we can conclude that:
Weight of 2 mangoes = Weight of 4 guavas.
Weight of 5 muskmelons = Weight of 15 mangoes.
Weight of 5 mangoes and 2 guavas = Weight of 2 muskmelons.
Note: Be careful in the calculation part, as the only mistake that can be committed in the above problem is in the calculation part. Also, don’t forget to convert all the masses to a single unit system, preferably the smallest among the ones used in the question to avoid decimal calculations.
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