Question

The wattage of an electric heater which draws 5A current when connected to a 200V supply is _ _ _ _ _ _ _ _ _ _ _ _ _ _ _ _

Answer 1

Hint: The term Power, it is the ability to do or act. Basically the capacity of doing or achieving something. Yeah in a simple term power is a rare thing for doing work. The Si unit of the power is Watt. It also measures in the Horse Power (hp).

Complete step by step solution:
Here, we know the value of the electric current and the electric potential, and we need to find the value of the electric power. So with this given condition we know the expression of electric power in terms of electric potential and the electric current.
So, the electric power is the product of the electric current to the electric potential. The expression for the given condition is
$
  Power = \left( {Electric\;Potential} \right) \times \left( {Electric\;Current} \right) \\
  P = V \times I \\
 $
Now, we put the value of the electric potential and the electric current.
P = 220 * 5
P = 1100 Watt
So, the power of an electric heater of given condition is 1100 Watt.

Note: The power is negative too. It is basically a signed quantity. The negative sign represents the positive power is in the opposite direction.
Power can be calculated in terms of work and time. The expression is
$Power = \dfrac{{Work}}{{Time}}$
Power can be calculated in terms of energy and time. The expression is
$Power = \dfrac{{Energy}}{{Time}}$
Power can be calculated in terms of electric current and electric resistance. The expression is
$
  Power = {\left( {Electric\;Current} \right)^2} \times \left( {Electric\;\operatorname{Re} sis\tan ce} \right) \\
  P = {I^2} \times R \\
 $
Power can be calculated in terms of electric potential and electric resistance. The expression is
$
  Power = \left[ {\dfrac{{{{\left( {Electric\;Potential} \right)}^2}}}{{\left( {Electric\;\operatorname{Re} sis\tan ce} \right)}}} \right] \\
  P = \left[ {\dfrac{{{V^2}}}{R}} \right] \\
 $
Power can be calculated in terms of electric potential and electric current. The expression is
$
  Power = \left( {Electric\;Current} \right) \times \left( {Electric\;Potential} \right) \\
  P = I \times V \\
 $