Answer
Verified
413.7k+ views
Hint:The inverse of the slope of curve in the V-I graph is the resistance of the diode. Use Ohm’s law to express the resistance of the diode and find the relation between resistance and slope of the curve. For the second part, the change in current is \[ - 1\,\mu A\].
Formula used:
According to Ohm’s law the resistance of the diode is given as,
\[R = \dfrac{{\Delta V}}{{\Delta I}}\]
Here, \[\Delta V\] is the potential across the diode and \[\Delta I\] is the change in the current.
Complete step by step answer:
We have from Ohm’s law the resistance of the diode is given as,
\[R = \dfrac{{\Delta V}}{{\Delta I}}\]
Here, \[\Delta V\] is the potential across the diode and \[\Delta I\] is the change in the current.
Therefore, if we look at the V-I graph of the diode, the resistance is the reciprocal of the slope of the curve. Thus, we can write,
\[R = \dfrac{1}{m} = \dfrac{{{V_2} - {V_1}}}{{{I_2} - {I_1}}}\]
Here, m is the slope of the curve.
(a) At \[{I_D} = 15\,{\text{mA}}\], let’s find the resistance of the diode as follows,
\[R = \dfrac{{{V_2} - {V_1}}}{{{I_2} - {I_1}}}\]
Substituting 0.8 for \[{V_2}\], 0.7 for \[{V_1}\], 20 A for \[{I_2}\] and 10 A for \[{I_1}\] in the above equation, we get,
\[R = \dfrac{{0.8 - 0.7}}{{\left( {20 - 10} \right) \times {{10}^{ - 3}}}}\]
\[ \therefore R = 10\,\Omega \]
Therefore, the resistance of the diode is \[10\,\Omega \].
(b) At \[{V_D} = - 10\,{\text{V}}\], let’s find the resistance of the diode as follows,
\[R = \dfrac{{{V_2} - {V_1}}}{{{I_2} - {I_1}}}\]
Substituting \[ - 10\,{\text{V}}\] for \[{V_2}\], 0 V for \[{V_1}\], \[ - 1\,\mu A\] for \[{I_2}\] and 0 A for \[{I_1}\] in the above equation, we get,
\[R = \dfrac{{ - 10 - 0}}{{\left( { - 1 - 0} \right) \times {{10}^{ - 6}}}}\]
\[ \therefore R = {10^5}\,\Omega \]
Therefore, the resistance of the diode at \[{V_D} = - 10\,{\text{V}}\] is\[{10^5}\,\Omega \].
Note: In I-V characteristics graph, always denote the voltage along the x-axis and current along the y-axis. The reciprocal of the slope is the resistance of the diode and not the slope of the curve. Note that the resistance of the diode is always the positive quantity.
Formula used:
According to Ohm’s law the resistance of the diode is given as,
\[R = \dfrac{{\Delta V}}{{\Delta I}}\]
Here, \[\Delta V\] is the potential across the diode and \[\Delta I\] is the change in the current.
Complete step by step answer:
We have from Ohm’s law the resistance of the diode is given as,
\[R = \dfrac{{\Delta V}}{{\Delta I}}\]
Here, \[\Delta V\] is the potential across the diode and \[\Delta I\] is the change in the current.
Therefore, if we look at the V-I graph of the diode, the resistance is the reciprocal of the slope of the curve. Thus, we can write,
\[R = \dfrac{1}{m} = \dfrac{{{V_2} - {V_1}}}{{{I_2} - {I_1}}}\]
Here, m is the slope of the curve.
(a) At \[{I_D} = 15\,{\text{mA}}\], let’s find the resistance of the diode as follows,
\[R = \dfrac{{{V_2} - {V_1}}}{{{I_2} - {I_1}}}\]
Substituting 0.8 for \[{V_2}\], 0.7 for \[{V_1}\], 20 A for \[{I_2}\] and 10 A for \[{I_1}\] in the above equation, we get,
\[R = \dfrac{{0.8 - 0.7}}{{\left( {20 - 10} \right) \times {{10}^{ - 3}}}}\]
\[ \therefore R = 10\,\Omega \]
Therefore, the resistance of the diode is \[10\,\Omega \].
(b) At \[{V_D} = - 10\,{\text{V}}\], let’s find the resistance of the diode as follows,
\[R = \dfrac{{{V_2} - {V_1}}}{{{I_2} - {I_1}}}\]
Substituting \[ - 10\,{\text{V}}\] for \[{V_2}\], 0 V for \[{V_1}\], \[ - 1\,\mu A\] for \[{I_2}\] and 0 A for \[{I_1}\] in the above equation, we get,
\[R = \dfrac{{ - 10 - 0}}{{\left( { - 1 - 0} \right) \times {{10}^{ - 6}}}}\]
\[ \therefore R = {10^5}\,\Omega \]
Therefore, the resistance of the diode at \[{V_D} = - 10\,{\text{V}}\] is\[{10^5}\,\Omega \].
Note: In I-V characteristics graph, always denote the voltage along the x-axis and current along the y-axis. The reciprocal of the slope is the resistance of the diode and not the slope of the curve. Note that the resistance of the diode is always the positive quantity.
Recently Updated Pages
Mark and label the given geoinformation on the outline class 11 social science CBSE
When people say No pun intended what does that mea class 8 english CBSE
Name the states which share their boundary with Indias class 9 social science CBSE
Give an account of the Northern Plains of India class 9 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE
Advantages and disadvantages of science
Trending doubts
Bimbisara was the founder of dynasty A Nanda B Haryanka class 6 social science CBSE
Which are the Top 10 Largest Countries of the World?
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE
10 examples of evaporation in daily life with explanations
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
How do you graph the function fx 4x class 9 maths CBSE
Difference Between Plant Cell and Animal Cell