Question

The values of four quantum numbers of valence electrons in an element X are \[n = 4,I = 0,m = 0\] , s= \[s = \dfrac{1}{2}\] The element is:
A.K
B.Ti
C.Na
D.Sc

Answer 1

Hint:As we know quantum number shows the values of conserved quantities in the dynamics. There are four quantum numbers n, l, m and s. Each factor describes a particular factor that is the property of the electron. These equations are not needed. The value of each electron assigned by the quantum number with building up. It describes a set of values which state electrons during its distance from the nucleus.
Complete step by step answer:
Here we see a total of four quantum numbers: The principal quantum number (n), the orbital angular momentum Quantum number (l), the magnetic quantum number (m) and the electron spin number (s). here every quantum number describes different things. Quantum number designates the principle of the electron shell. L determines the shape of the orbital, m determines the number of orbitals and orientation within the subshell, spin number does not depend on quantum number.
Here we see the \[s = \dfrac{1}{2}\] , which describes the valence electron is in 4s orbital, so the possible elements are K and Ca.
So, option (A) is the correct answer.

Note:The elements are possible to find by the values of four quantum numbers and it describes valence electrons in elements. We know about the description of four quantum numbers and what role it in the formation of elements. Four quantum numbers are always kept in fixed values of elements.