
The value power $P_1$ is
A. 1000W
B. 975W
C. 25W
D. 200W
Answer
553.2k+ views
Hint: The equation of power is useful here .we can use different equations of power to find it. Here, the circuit is in series connection. So the total power will be the sum of two individual powers. Power is the work done in unit time. That means how much energy has been used within a short span of time.
Complete answer:
First of all we have to understand the equations of power.
$\begin{align}
& P=EI \\
& P={{I}^{2}}R \\
\end{align}$
Where, E is the voltage supplied to the circuit.
I is the current flowing through the circuit.
R is the Resistance.
Now, let us find the current flowing through the circuit. Current is given by the ohms law as,
$I=\dfrac{V}{R}$
Here, the resistance is in series connection. So,
$R={{R}_{1}}+{{R}_{2}}=1+39=40\Omega $
Now, current will be given as,
$I=\dfrac{V}{R}=\dfrac{E}{R}=\dfrac{200}{40}=5A$
We know that total power of the combination will be,
$\begin{align}
& P={{I}^{2}}R \\
& \Rightarrow P={{\left( 5 \right)}^{2}}\times 40=1000W \\
\end{align}$
Therefore total power = 1000W
Now let’s find power dissipated at the first bulb. The resistance of the first bulb is 1 ohm. So,
$\begin{align}
& {{P}_{1}}={{I}^{2}}R \\
& \Rightarrow {{P}_{1}}={{\left( 5 \right)}^{2}}\times 1=25W \\
\end{align}$
Therefore the power dissipated at the first bulb is ${{P}_{1}}=25W$.
So, the correct answer is “Option C”.
Additional Information:
power is the force acting per unit time period. Power is the amount of force applied in a short period of time. The S.I unit of power is watt. The concept of power is having a great role in our daily life. Electric power is measured in kilowatt hour.
Power can be represented by so many equations like,
$\begin{align}
& P=F\times \upsilon \\
& P=\dfrac{E}{t} \\
& P=V\times I \\
& P={{I}^{2}}\times R \\
& P=\dfrac{{{V}^{2}}}{R} \\
\end{align}$
Power can be found out by multiplying force and velocity. Power is the energy per unit time. So by that way also we can find the value of power. Another way to find power is the product of the square of current and resistance of the material used. Current term can be replaced by voltage by the usage of ohm’s law.
So basically power is energy involved per time period. In physics more power means more energy can be used up in a very short span of time. Value of power decreases as the time span increases.
Note:
The power can be found out easily, Even though the unit of the current, voltage and resistance should be noted well. Faults in their units may lead to wrong answers.
Complete answer:
First of all we have to understand the equations of power.
$\begin{align}
& P=EI \\
& P={{I}^{2}}R \\
\end{align}$
Where, E is the voltage supplied to the circuit.
I is the current flowing through the circuit.
R is the Resistance.
Now, let us find the current flowing through the circuit. Current is given by the ohms law as,
$I=\dfrac{V}{R}$
Here, the resistance is in series connection. So,
$R={{R}_{1}}+{{R}_{2}}=1+39=40\Omega $
Now, current will be given as,
$I=\dfrac{V}{R}=\dfrac{E}{R}=\dfrac{200}{40}=5A$
We know that total power of the combination will be,
$\begin{align}
& P={{I}^{2}}R \\
& \Rightarrow P={{\left( 5 \right)}^{2}}\times 40=1000W \\
\end{align}$
Therefore total power = 1000W
Now let’s find power dissipated at the first bulb. The resistance of the first bulb is 1 ohm. So,
$\begin{align}
& {{P}_{1}}={{I}^{2}}R \\
& \Rightarrow {{P}_{1}}={{\left( 5 \right)}^{2}}\times 1=25W \\
\end{align}$
Therefore the power dissipated at the first bulb is ${{P}_{1}}=25W$.
So, the correct answer is “Option C”.
Additional Information:
power is the force acting per unit time period. Power is the amount of force applied in a short period of time. The S.I unit of power is watt. The concept of power is having a great role in our daily life. Electric power is measured in kilowatt hour.
Power can be represented by so many equations like,
$\begin{align}
& P=F\times \upsilon \\
& P=\dfrac{E}{t} \\
& P=V\times I \\
& P={{I}^{2}}\times R \\
& P=\dfrac{{{V}^{2}}}{R} \\
\end{align}$
Power can be found out by multiplying force and velocity. Power is the energy per unit time. So by that way also we can find the value of power. Another way to find power is the product of the square of current and resistance of the material used. Current term can be replaced by voltage by the usage of ohm’s law.
So basically power is energy involved per time period. In physics more power means more energy can be used up in a very short span of time. Value of power decreases as the time span increases.
Note:
The power can be found out easily, Even though the unit of the current, voltage and resistance should be noted well. Faults in their units may lead to wrong answers.
Recently Updated Pages
Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

If overrightarrow a overrightarrow b overrightarrow class 12 maths CBSE

If a b and c are unit coplanar vectors then left 2a class 12 maths CBSE

Master Class 12 Economics: Engaging Questions & Answers for Success

Trending doubts
Which are the Top 10 Largest Countries of the World?

What are the major means of transport Explain each class 12 social science CBSE

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Give 10 examples of unisexual and bisexual flowers

