The total number of \[\sigma \] and \[\pi \] bonds present in azobenzene are:
A.24 \[\sigma \] , 6 \[\pi \]
B.25 \[\sigma \], 7 \[\pi \]
C.28 \[\sigma \], 6 \[\pi \]
D.27 \[\sigma \], 6 \[\pi \]
Answer
602.1k+ views
Hint: To obtain the solution of this question, we must first understand the concept of \[\sigma \] bonds and \[\pi \] bonds. Then we must draw the molecular structure of azobenzene and then individually count \[\sigma \] bonds and \[\pi \] bonds.
Complete step by step answer:
Before proceeding with the solution of this question, let us understand some basic concepts and terms:
\[\sigma \] and \[\pi \] bonds are both covalent in nature
\[\sigma \] bonds are formed when there is end to end overlapping of orbitals. It can also be represented as a single bond
\[\pi \] bonds are formed when there is overlapping of a lobe of one atomic orbital. It can also be represented as a double bond.
The bond strength of \[\sigma \] bonds is stronger than \[\pi \] bonds
The structure of Azobenzene can be given by:
From this structure, we can observe that the number of single and double bonds are:
Number of single bonds = 25 = number of \[\sigma \] bonds
Number of double bonds = 7 = number of \[\pi \] bonds
Hence, there are 25 \[\sigma \] bonds and 7 \[\pi \] bonds
Hence, Option B is the correct option.
Note:
Azobenzene is a molecule whose structure comprises two phenyl rings linked by a N=N double bond; the parent compound of the azobenzene class of compounds. One of the largest applications of the compound azobenzene takes place in the colouring and dye industry.
Complete step by step answer:
Before proceeding with the solution of this question, let us understand some basic concepts and terms:
\[\sigma \] and \[\pi \] bonds are both covalent in nature
\[\sigma \] bonds are formed when there is end to end overlapping of orbitals. It can also be represented as a single bond
\[\pi \] bonds are formed when there is overlapping of a lobe of one atomic orbital. It can also be represented as a double bond.
The bond strength of \[\sigma \] bonds is stronger than \[\pi \] bonds
The structure of Azobenzene can be given by:
From this structure, we can observe that the number of single and double bonds are:
Number of single bonds = 25 = number of \[\sigma \] bonds
Number of double bonds = 7 = number of \[\pi \] bonds
Hence, there are 25 \[\sigma \] bonds and 7 \[\pi \] bonds
Hence, Option B is the correct option.
Note:
Azobenzene is a molecule whose structure comprises two phenyl rings linked by a N=N double bond; the parent compound of the azobenzene class of compounds. One of the largest applications of the compound azobenzene takes place in the colouring and dye industry.
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