
The total number of marks obtained in Feb 02 is what percent of the total marks obtained in April 01 using the plot given below?
(a) 110%
(b) 112.5%
(c) 115%
(d) 116.5%
Answer
564.3k+ views
Hint: We start solving the problem by finding the total number of marks obtained in Feb 02 and the total number of marks obtained in April 01. We then find the percentage of marks obtained in Feb 02 to the marks obtained in April 01 using the formula that the percentage of x out of y is calculated as $\dfrac{x}{y}\times 100$.
Complete step by step answer:
According to the problem, we need to find what percent of the total marks obtained in Feb 02 is with the total number of marks obtained in April 01.
From the plot we can see that the total marks obtained in Feb 02 is 405 out of 500 and also the total marks obtained in Apr 01 is 360 out of 500.
Now, we need to find what is the percentage of 405 out of 360. Let us assume the required percentage be p%.
We know that the percentage of x out of y is calculated as $\dfrac{x}{y}\times 100$.
So, we get $p=\dfrac{405}{360}\times 100$.
$\Rightarrow p=\dfrac{9}{8}\times 100$.
$\Rightarrow p=1.125\times 100$.
$\Rightarrow p=112.5\%$.
So, we have found that the total number of marks obtained in Feb 02 is 112.5% of the total marks obtained in April 01.
So, the correct answer is “Option B”.
Note: We should not make calculation mistakes while solving this problem. We can also calculate the average of the marks obtained in all the examinations. We should not think that the percentage should be less than 100 while calculating this type of problems as this will not be true every time. Similarly, we can expect problems to find the mean, median and mode of the total marks given in the graph.
Complete step by step answer:
According to the problem, we need to find what percent of the total marks obtained in Feb 02 is with the total number of marks obtained in April 01.
From the plot we can see that the total marks obtained in Feb 02 is 405 out of 500 and also the total marks obtained in Apr 01 is 360 out of 500.
Now, we need to find what is the percentage of 405 out of 360. Let us assume the required percentage be p%.
We know that the percentage of x out of y is calculated as $\dfrac{x}{y}\times 100$.
So, we get $p=\dfrac{405}{360}\times 100$.
$\Rightarrow p=\dfrac{9}{8}\times 100$.
$\Rightarrow p=1.125\times 100$.
$\Rightarrow p=112.5\%$.
So, we have found that the total number of marks obtained in Feb 02 is 112.5% of the total marks obtained in April 01.
So, the correct answer is “Option B”.
Note: We should not make calculation mistakes while solving this problem. We can also calculate the average of the marks obtained in all the examinations. We should not think that the percentage should be less than 100 while calculating this type of problems as this will not be true every time. Similarly, we can expect problems to find the mean, median and mode of the total marks given in the graph.
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