
The solubility of a solute is 8. If the density of solution is \[1.364{\text{ }}gm/mL\], find the weight-volume percentage.
A.5.103g/ml
B.10.103g/ml
C.8.103g/ml
D.12.103b/ml
Answer
568.8k+ views
Hint: Solubility here is 8 gm present in 100 mL of solvent so calculate mass and then volume and finally weight-volume percentage. This information can easily take to the answer if properly analyzed and calculated.
Complete step by step answer:
In the given question, the concept asked is on solubility and then using density we need to find weight- volume percentage. Before proceeding directly to the calculation part of the answer let us know first what the solubility is and how it will be used in this question to find weight-volume percentage.
Coming to the question, given that the solubility is 8 and that means 8 gm of solute in 100gm of solvent. Therefore, the total mass of the solution present over here is 108 gm (100 gm solvent and 8 gm solute)
We know that $Density = \dfrac{{mass}}{{volume}}$ and therefore, mass we have calculated and we know the density of the solution from the provided data in the question. So, we can find out the volume of solution which is represented as: -
$1.364gm/mL = \dfrac{{108gm}}{{volume}}$
So, volume = $\dfrac{{108gm}}{{1.364gm/mL}} = 79.18mL$.
We have the volume with us and now we have to calculate weight-volume percentage. So, this weight-volume percentage is defined as the mass of solute present in the volume of solvent.
This weight-volume percentage calculation is represented as: -
\[Weight - volume{\text{ }}\% {\text{ }} = \dfrac{{weight{\text{ }}of{\text{ }}solute}}{{volume{\text{ }}of{\text{ }}solvent}} \times 100 = \dfrac{8}{{79.18}} \times 100 = 10.103\% \]
So, the weight-volume percentage of the solution is \[{\mathbf{10}}.{\mathbf{103}}{\text{ }}\% \]
Hence option B is correct.
Note:
Solubility is defined as the maximum amount of solute that can be dissolved in a given amount of solvent at a certain temperature. For example, you dissolved 50 gm of salt in 100 mL of water and if you add more salt it won’t get dissolved, so the solubility becomes 50 (just a hypothetical situation).
Complete step by step answer:
In the given question, the concept asked is on solubility and then using density we need to find weight- volume percentage. Before proceeding directly to the calculation part of the answer let us know first what the solubility is and how it will be used in this question to find weight-volume percentage.
Coming to the question, given that the solubility is 8 and that means 8 gm of solute in 100gm of solvent. Therefore, the total mass of the solution present over here is 108 gm (100 gm solvent and 8 gm solute)
We know that $Density = \dfrac{{mass}}{{volume}}$ and therefore, mass we have calculated and we know the density of the solution from the provided data in the question. So, we can find out the volume of solution which is represented as: -
$1.364gm/mL = \dfrac{{108gm}}{{volume}}$
So, volume = $\dfrac{{108gm}}{{1.364gm/mL}} = 79.18mL$.
We have the volume with us and now we have to calculate weight-volume percentage. So, this weight-volume percentage is defined as the mass of solute present in the volume of solvent.
This weight-volume percentage calculation is represented as: -
\[Weight - volume{\text{ }}\% {\text{ }} = \dfrac{{weight{\text{ }}of{\text{ }}solute}}{{volume{\text{ }}of{\text{ }}solvent}} \times 100 = \dfrac{8}{{79.18}} \times 100 = 10.103\% \]
So, the weight-volume percentage of the solution is \[{\mathbf{10}}.{\mathbf{103}}{\text{ }}\% \]
Hence option B is correct.
Note:
Solubility is defined as the maximum amount of solute that can be dissolved in a given amount of solvent at a certain temperature. For example, you dissolved 50 gm of salt in 100 mL of water and if you add more salt it won’t get dissolved, so the solubility becomes 50 (just a hypothetical situation).
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