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Question

Answers

A. $0.37{m^2}$

B. $0.47{m^2}$

C. $0.88{m^2}$

D. $0.67{m^2}$

Answer
Verified

Diagram:

A trapezium is a quadrilateral having a pair of lines parallel to each other. For a trapezium ABCD, having AB and CD as parallel lines, the height of a trapezium is defined as the distance between the parallel lines AB and CD

Now, we know the formula for the area of a trapezium, i.e.

$A = \dfrac{1}{2}h\left( {a + b} \right)$

where A is the area of trapezium,

$h$is the height of trapezium or the distance between the parallel lines,

$a$and $b$are the parallel sides of trapezium,

Now according to given data, parallel sides are $1m$ and $1.2m$ and perpendicular distance between the parallel lines is $0.8m$

$\Rightarrow a = 1m$

$\Rightarrow b = 1.2m$

$\Rightarrow h = 0.8m$

Using the above formula, and substituting the above values

$A = \dfrac{1}{2}h\left( {a + b} \right)$

Area of trapezium is:

$A = \dfrac{1}{2} \times 0.8 \times \left( {1 + 1.2} \right){m^2}$

$\Rightarrow A = \dfrac{1}{2} \times 0.8 \times 2.2{m^2}$

$\Rightarrow A = 0.4 \times 2.2{m^2}$

$\Rightarrow A = 0.88{m^2}$

Thus, Area of trapezium calculated by above formula is $0.88{m^2}$

Hence,

Area of square with side a: ${a^2}$

Area of a triangle with base ‘b’ and height ‘h’:$\dfrac{1}{2} \times b \times h$

Area of circle with radius r: $\pi {r^2}$

Area of the rectangle with length l and breadth b: $l \times b$