
The results of half yearly and annual examinations are shown in the table given below:
Results No. of students in section A No. of students in section B No. of students in section C No. of students in section D Students failed in both exams 28 23 17 27 Students failed in half yearly but passed in annual exam 14 12 8 13 Students passed in half yearly but failed in annual exam 6 17 9 15 Students passed in both exams 64 55 46 76
Which section has the minimum failure rate in half yearly?
(a) A section
(b) B section
(c) C section
(d) D section
| Results | No. of students in section A | No. of students in section B | No. of students in section C | No. of students in section D |
| Students failed in both exams | 28 | 23 | 17 | 27 |
| Students failed in half yearly but passed in annual exam | 14 | 12 | 8 | 13 |
| Students passed in half yearly but failed in annual exam | 6 | 17 | 9 | 15 |
| Students passed in both exams | 64 | 55 | 46 | 76 |
Answer
565.2k+ views
Hint: We start solving the problem by finding the total number of students present in each section by adding the no. of students who passed and failed in each category given in the table. We then find the total no. of students failed in half yearly examinations in each section using the data given in the table. We then find the failure rate in half yearly by dividing the total number of students failed in half yearly in a section with the total no. of students present in that section. We then compare results and find the section with minimum failure rate.
Complete step by step answer:
According to the problem, we have given the results of half yearly and annual examinations in the table as shown below and we need to find which section has the minimum failure rate in half yearly examination.
Let us find the total number of students present in each section.
From the table, we can see that section A has a total of $\left( 28+14+6+64 \right)=112$ students.
Similarly, we can see that section B has a total of $\left( 23+12+17+55 \right)=107$ students.
Similarly, we can see that section C has a total of $\left( 17+8+9+46 \right)=80$ students.
Similarly, we can see that section B has a total of $\left( 27+13+15+76 \right)=131$ students.
Now, let us find the total no. of students failed in half yearly examination in each section.
From the table, we can see that section A has a total of $\left( 28+14 \right)=42$ students failed in half yearly examination.
Similarly, we can see that section B has a total of $\left( 23+12 \right)=35$ students failed in half yearly examinations.
Similarly, we can see that section C has a total of $\left( 17+8 \right)=25$ students failed in half yearly examinations.
Similarly, we can see that section D has a total of $\left( 27+13 \right)=40$ students failed in half yearly examinations.
Now, let us find the failure rate in the half yearly examination for each section.
We know that failure rate = $\dfrac{\text{Total number of students failed in half-yearly examination in the section}}{\text{Total number of students present in that section}}$.
Failure rate for section A = $\dfrac{42}{112}\times 100=37.5\%$.
Failure rate for section B = $\dfrac{35}{107}\times 100=32.7\%$.
Failure rate for section C = $\dfrac{25}{80}\times 100=31.3\%$.
Failure rate for section D = $\dfrac{40}{131}\times 100=30.5\%$.
We can see that section D has a minimum failure rate in half yearly examinations.
∴ Section D has a minimum failure rate in half yearly examinations.
So, the correct answer is “Option d”.
Note: We should not assume that students failed in both exams includes students failed in only half-yearly exams and students failed only in annual exams which is the common mistake many of us can make. We take percentage for the failure rate to get a better view about the results obtained as comparing the decimals will give confusion. Similarly, we can also expect the problems to find the total failure rate of the school and total pass rate of each section and school.
Complete step by step answer:
According to the problem, we have given the results of half yearly and annual examinations in the table as shown below and we need to find which section has the minimum failure rate in half yearly examination.
| Results | No. of students in section A | No. of students in section B | No. of students in section C | No. of students in section D |
| Students failed in both exams | 28 | 23 | 17 | 27 |
| Students failed in half yearly but passed in annual exam | 14 | 12 | 8 | 13 |
| Students passed in half yearly but failed in annual exam | 6 | 17 | 9 | 15 |
| Students passed in both exams | 64 | 55 | 46 | 76 |
Let us find the total number of students present in each section.
From the table, we can see that section A has a total of $\left( 28+14+6+64 \right)=112$ students.
Similarly, we can see that section B has a total of $\left( 23+12+17+55 \right)=107$ students.
Similarly, we can see that section C has a total of $\left( 17+8+9+46 \right)=80$ students.
Similarly, we can see that section B has a total of $\left( 27+13+15+76 \right)=131$ students.
Now, let us find the total no. of students failed in half yearly examination in each section.
From the table, we can see that section A has a total of $\left( 28+14 \right)=42$ students failed in half yearly examination.
Similarly, we can see that section B has a total of $\left( 23+12 \right)=35$ students failed in half yearly examinations.
Similarly, we can see that section C has a total of $\left( 17+8 \right)=25$ students failed in half yearly examinations.
Similarly, we can see that section D has a total of $\left( 27+13 \right)=40$ students failed in half yearly examinations.
Now, let us find the failure rate in the half yearly examination for each section.
We know that failure rate = $\dfrac{\text{Total number of students failed in half-yearly examination in the section}}{\text{Total number of students present in that section}}$.
Failure rate for section A = $\dfrac{42}{112}\times 100=37.5\%$.
Failure rate for section B = $\dfrac{35}{107}\times 100=32.7\%$.
Failure rate for section C = $\dfrac{25}{80}\times 100=31.3\%$.
Failure rate for section D = $\dfrac{40}{131}\times 100=30.5\%$.
We can see that section D has a minimum failure rate in half yearly examinations.
∴ Section D has a minimum failure rate in half yearly examinations.
So, the correct answer is “Option d”.
Note: We should not assume that students failed in both exams includes students failed in only half-yearly exams and students failed only in annual exams which is the common mistake many of us can make. We take percentage for the failure rate to get a better view about the results obtained as comparing the decimals will give confusion. Similarly, we can also expect the problems to find the total failure rate of the school and total pass rate of each section and school.
Recently Updated Pages
Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Master Class 9 English: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Which places in India experience sunrise first and class 9 social science CBSE

Fill the blanks with the suitable prepositions 1 The class 9 english CBSE

Write the 6 fundamental rights of India and explain in detail

Difference Between Plant Cell and Animal Cell

What is pollution? How many types of pollution? Define it

What is the Full Form of ISI and RAW

