
The reading of the ammeter shown in the figure is?
\[(A)6.56{\text{ }}A\]
\[(B)3.28{\text{ }}A\]
\[(C)2.18{\text{ }}A\]
\[(D)1.09{\text{ }}A\]
Answer
503.1k+ views
Hint: An ammeter (A) is linked in series to measure current. In this circuit, the meter receives all of the currents. Here, we have to find the value of ammeter reading. Because of finding its value, we should know about the formula for current. As we are applying the value of Voltage and resistance value in the current equation we will get a result which is known as a value of ammeter reading.
Formula used:
$I = \dfrac{V}{R}$
Complete step by step solution:
The circuit illustrated in the figure can simplify from the supplied circuit.
The circuit's corresponding resistance is:
${R_{eq}} = \dfrac{{2 \times 4}}{{2 + 4}} + 0.8$
As we are calculating this value,
We will get the value of ${R_{eq}}$,
${R_{eq}} = 2.13\Omega $
Applying this ${R_{eq}}$ value is given formula $I = \dfrac{V}{R}$.
Therefore,
The circuit will draw the following current:
$I = \dfrac{{14}}{{2.13}}$
By dividing this equation, the $I$value will be,
\[ \Rightarrow 6.56A\]
The current going through the ammeter is now calculated as follows:
\[{I_A} = I \times \dfrac{2}{{2 + 4}}\]
As we are applying $I$ value in the above equation we will get,
${I_A} = 6.56 \times \dfrac{2}{6}$
Calculated this formation We will receive the value of ${I_A}$ is,
${I_A} = 2.18A$
Hence, Option (C) is the correct answer.
Note: An ammeter is a device that measures direct or alternating electric current in amperes. An ammeter can measure a wide range of current values since only a small portion of the current is routed through the meter mechanism at high current values. A shunt running parallel to the meter carries the majority of the current.
Formula used:
$I = \dfrac{V}{R}$
Complete step by step solution:
The circuit illustrated in the figure can simplify from the supplied circuit.
The circuit's corresponding resistance is:
${R_{eq}} = \dfrac{{2 \times 4}}{{2 + 4}} + 0.8$
As we are calculating this value,
We will get the value of ${R_{eq}}$,
${R_{eq}} = 2.13\Omega $
Applying this ${R_{eq}}$ value is given formula $I = \dfrac{V}{R}$.
Therefore,
The circuit will draw the following current:
$I = \dfrac{{14}}{{2.13}}$
By dividing this equation, the $I$value will be,
\[ \Rightarrow 6.56A\]
The current going through the ammeter is now calculated as follows:
\[{I_A} = I \times \dfrac{2}{{2 + 4}}\]
As we are applying $I$ value in the above equation we will get,
${I_A} = 6.56 \times \dfrac{2}{6}$
Calculated this formation We will receive the value of ${I_A}$ is,
${I_A} = 2.18A$
Hence, Option (C) is the correct answer.
Note: An ammeter is a device that measures direct or alternating electric current in amperes. An ammeter can measure a wide range of current values since only a small portion of the current is routed through the meter mechanism at high current values. A shunt running parallel to the meter carries the majority of the current.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Why cannot DNA pass through cell membranes class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

In a human foetus the limbs and digits develop after class 12 biology CBSE

AABbCc genotype forms how many types of gametes a 4 class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

The correct structure of ethylenediaminetetraacetic class 12 chemistry CBSE

