
The reading of the ammeter shown in the figure is?
\[(A)6.56{\text{ }}A\]
\[(B)3.28{\text{ }}A\]
\[(C)2.18{\text{ }}A\]
\[(D)1.09{\text{ }}A\]
Answer
489.3k+ views
Hint: An ammeter (A) is linked in series to measure current. In this circuit, the meter receives all of the currents. Here, we have to find the value of ammeter reading. Because of finding its value, we should know about the formula for current. As we are applying the value of Voltage and resistance value in the current equation we will get a result which is known as a value of ammeter reading.
Formula used:
$I = \dfrac{V}{R}$
Complete step by step solution:
The circuit illustrated in the figure can simplify from the supplied circuit.
The circuit's corresponding resistance is:
${R_{eq}} = \dfrac{{2 \times 4}}{{2 + 4}} + 0.8$
As we are calculating this value,
We will get the value of ${R_{eq}}$,
${R_{eq}} = 2.13\Omega $
Applying this ${R_{eq}}$ value is given formula $I = \dfrac{V}{R}$.
Therefore,
The circuit will draw the following current:
$I = \dfrac{{14}}{{2.13}}$
By dividing this equation, the $I$value will be,
\[ \Rightarrow 6.56A\]
The current going through the ammeter is now calculated as follows:
\[{I_A} = I \times \dfrac{2}{{2 + 4}}\]
As we are applying $I$ value in the above equation we will get,
${I_A} = 6.56 \times \dfrac{2}{6}$
Calculated this formation We will receive the value of ${I_A}$ is,
${I_A} = 2.18A$
Hence, Option (C) is the correct answer.
Note: An ammeter is a device that measures direct or alternating electric current in amperes. An ammeter can measure a wide range of current values since only a small portion of the current is routed through the meter mechanism at high current values. A shunt running parallel to the meter carries the majority of the current.
Formula used:
$I = \dfrac{V}{R}$
Complete step by step solution:
The circuit illustrated in the figure can simplify from the supplied circuit.
The circuit's corresponding resistance is:
${R_{eq}} = \dfrac{{2 \times 4}}{{2 + 4}} + 0.8$
As we are calculating this value,
We will get the value of ${R_{eq}}$,
${R_{eq}} = 2.13\Omega $
Applying this ${R_{eq}}$ value is given formula $I = \dfrac{V}{R}$.
Therefore,
The circuit will draw the following current:
$I = \dfrac{{14}}{{2.13}}$
By dividing this equation, the $I$value will be,
\[ \Rightarrow 6.56A\]
The current going through the ammeter is now calculated as follows:
\[{I_A} = I \times \dfrac{2}{{2 + 4}}\]
As we are applying $I$ value in the above equation we will get,
${I_A} = 6.56 \times \dfrac{2}{6}$
Calculated this formation We will receive the value of ${I_A}$ is,
${I_A} = 2.18A$
Hence, Option (C) is the correct answer.
Note: An ammeter is a device that measures direct or alternating electric current in amperes. An ammeter can measure a wide range of current values since only a small portion of the current is routed through the meter mechanism at high current values. A shunt running parallel to the meter carries the majority of the current.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Differentiate between action potential and resting class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Explain sex determination in humans with the help of class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

