Answer
424.5k+ views
Hint: Here take the radius of hemisphere and the height of a right circular cylinder equal as given in the question. Now use the volume of hemisphere and right circular cylinder $\dfrac{{2\pi {r^3}}}{3}$ and $\pi {R^2}h$ respectively. So, by taking the ratio of volumes we will obtain the ratios of their radii.
Complete step-by-step answer:
Let radius of hemisphere be r,
Let height of a right circular cylinder be h and
Let the radius of a right circular cylinder be R.
Now, $r = h$, as it is given that the radius of the hemisphere and the height of a right circular cylinder are equal.
Now we know that,
Volume of hemisphere is $\dfrac{{2\pi {r^3}}}{3}$ -(1)
Volume of right circular cylinder is $\pi {R^2}h$ -(2)
Now we will consider the ratio of volume of hemisphere and cylinder,
\[
volume{\text{ of hemisphere : volume of right circular cylinder}} \\
\dfrac{{2\pi {r^3}}}{3}:\pi {R^2}h \\
{\text{2}}{{\text{r}}^3}:3{R^2}h \\
{\text{ }} \\
\]
Now using $r = h$,
\[{\text{2}}{{\text{r}}^2}:3{R^2}\]
$
\sqrt 2 r:\sqrt 3 R \\
\dfrac{r}{{\sqrt 3 }}:\dfrac{R}{{\sqrt 2 }} \\
\dfrac{r}{R} = \dfrac{{\sqrt 3 }}{{\sqrt 2 }} \\
\dfrac{r}{R} = \sqrt {1.5} \\
\dfrac{r}{R} = 1.2247 \\
$
So, the ratio of the radii of the hemisphere and the right circular cylinder is $1.2247$ approximately.
Note: We should note that if
$
\dfrac{x}{a}:\dfrac{y}{b} \\
\\
$
Then we say that
$\dfrac{x}{y} = \dfrac{a}{b}$
Which means the ratio of x and y is $\dfrac{a}{b}$.
Complete step-by-step answer:
Let radius of hemisphere be r,
Let height of a right circular cylinder be h and
Let the radius of a right circular cylinder be R.
Now, $r = h$, as it is given that the radius of the hemisphere and the height of a right circular cylinder are equal.
Now we know that,
Volume of hemisphere is $\dfrac{{2\pi {r^3}}}{3}$ -(1)
Volume of right circular cylinder is $\pi {R^2}h$ -(2)
Now we will consider the ratio of volume of hemisphere and cylinder,
\[
volume{\text{ of hemisphere : volume of right circular cylinder}} \\
\dfrac{{2\pi {r^3}}}{3}:\pi {R^2}h \\
{\text{2}}{{\text{r}}^3}:3{R^2}h \\
{\text{ }} \\
\]
Now using $r = h$,
\[{\text{2}}{{\text{r}}^2}:3{R^2}\]
$
\sqrt 2 r:\sqrt 3 R \\
\dfrac{r}{{\sqrt 3 }}:\dfrac{R}{{\sqrt 2 }} \\
\dfrac{r}{R} = \dfrac{{\sqrt 3 }}{{\sqrt 2 }} \\
\dfrac{r}{R} = \sqrt {1.5} \\
\dfrac{r}{R} = 1.2247 \\
$
So, the ratio of the radii of the hemisphere and the right circular cylinder is $1.2247$ approximately.
Note: We should note that if
$
\dfrac{x}{a}:\dfrac{y}{b} \\
\\
$
Then we say that
$\dfrac{x}{y} = \dfrac{a}{b}$
Which means the ratio of x and y is $\dfrac{a}{b}$.
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