
The plot $E$ Vs $r$ can be properly represented by
(A)
(B)
(C)
(D) None of these
Answer
547.2k+ views
Hint : First of all we should know about the Electric field, hence Electric field is the region around a charged particle or object within which its influence or a force would be experienced or exerted on other charged particles or objects.
Electric field which is produced by the stationary charges, and the magnetic field is produced by the moving charges (currents); these two are often described as the sources of the field.
Complete step by step solution:
The electrostatic force per unit charge is termed as the Electric Field. The direction of the field is taken to be the direction of the force it would exert on a positive test charge. The electric field is radially outward From a positive charge the electric field is radially outward and radially in toward a negative point charge.
The electrostatic force exerted by a point charge on a test charge at a r distance mainly depends upon the charge on both the charges, as well as the distance between the two.
As we know, for a shell of a radius and Q charge, the electric field is given by-
For a point inside the shell is when $ r < a $ , the field E=0
For point on or outside the shell is when $ r > R $ the field $ E = \dfrac{{kq}}{{{r^2}}} $
Thus, the graph (A) is correct.
Note:
Electric field, an electric property associated with each point in space when charge is present in any form. Electric field’s direction and magnitude are expressed by the value E, which is called the electric field strength or electric field intensity or simply the electric field.
Electric field which is produced by the stationary charges, and the magnetic field is produced by the moving charges (currents); these two are often described as the sources of the field.
Complete step by step solution:
The electrostatic force per unit charge is termed as the Electric Field. The direction of the field is taken to be the direction of the force it would exert on a positive test charge. The electric field is radially outward From a positive charge the electric field is radially outward and radially in toward a negative point charge.
The electrostatic force exerted by a point charge on a test charge at a r distance mainly depends upon the charge on both the charges, as well as the distance between the two.
As we know, for a shell of a radius and Q charge, the electric field is given by-
For a point inside the shell is when $ r < a $ , the field E=0
For point on or outside the shell is when $ r > R $ the field $ E = \dfrac{{kq}}{{{r^2}}} $
Thus, the graph (A) is correct.
Note:
Electric field, an electric property associated with each point in space when charge is present in any form. Electric field’s direction and magnitude are expressed by the value E, which is called the electric field strength or electric field intensity or simply the electric field.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

How much time does it take to bleed after eating p class 12 biology CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

