
The pH value of 100 litre aqueous solution containing 4 gram of \[{\text{NaOH}}\]?
A.3
B.9
C.11
D.14
Answer
573.3k+ views
Hint: The \[{\text{pH}}\] of a solution is defined as the negative logarithm to the base 10 of the hydrogen ion concentration is a solution. We shall calculate the moles of sodium hydroxide present and then its molarity. The molarity will be used to calculate the pH.
Formula Used: ${\text{molarity}} = \dfrac{{{\text{moles}}}}{{{\text{volume of solution}}}}$
${\text{pH = }} - {\text{lo}}{{\text{g}}_{{\text{10}}}}\left[ {{{\text{H}}^{\text{ + }}}} \right]$, where $\left[ {{{\text{H}}^{\text{ + }}}} \right]$ is the hydrogen ion concentration of the solution.
Complete step by step solution:
Since sodium hydroxide is a basic substance so we have to determine the \[{\text{pOH}}\] of the solution first since, \[{\text{pH + pOH }} = 14\]. Where, the \[{\text{pH}}\] is the negative logarithm to the base 10 hydroxyl ion concentration of the solution.
The molecular weight of sodium hydroxide = $23 + 16 + 1 = 40{\text{ g/mol}}$
Number of moles of 4 gram sodium hydroxide = $\dfrac{4}{{40}} = 0.1$ moles in 1 litre solution.
So in 100 litre the molarity will be = $\dfrac{{0.1}}{{100}} = 0.0001{\text{moles/ litre}}$.
The pOH of the solution = ${\text{pOH = }} - {\text{lo}}{{\text{g}}_{{\text{10}}}}\left[ {{\text{O}}{{\text{H}}^ - }} \right]$
Hence, \[{\text{pOH}}\]=${\text{ - lo}}{{\text{g}}_{{\text{10}}}}\left[ {{{10}^{ - 3}}} \right] = 3$.
The \[{\text{pH}} = 14 - {\text{pOH}} = 14 - 3 = 11\]
Hence, the correct answer is option C.
Note: pH is a very important factor in different conditions. The pH of a reaction can even alter the rate of a reaction. The pH of water determines the solubility and the precipitation of different salts. The pH of a solution can range from 0 to 14. Where 0 is the value of for the most acidic solution and 14 is the value of the most basic solution. The pOH scale is just the opposite of the pH scale and here the value of 0 is most the most basic solution, while 14 is the value of the most acidic solution.
Formula Used: ${\text{molarity}} = \dfrac{{{\text{moles}}}}{{{\text{volume of solution}}}}$
${\text{pH = }} - {\text{lo}}{{\text{g}}_{{\text{10}}}}\left[ {{{\text{H}}^{\text{ + }}}} \right]$, where $\left[ {{{\text{H}}^{\text{ + }}}} \right]$ is the hydrogen ion concentration of the solution.
Complete step by step solution:
Since sodium hydroxide is a basic substance so we have to determine the \[{\text{pOH}}\] of the solution first since, \[{\text{pH + pOH }} = 14\]. Where, the \[{\text{pH}}\] is the negative logarithm to the base 10 hydroxyl ion concentration of the solution.
The molecular weight of sodium hydroxide = $23 + 16 + 1 = 40{\text{ g/mol}}$
Number of moles of 4 gram sodium hydroxide = $\dfrac{4}{{40}} = 0.1$ moles in 1 litre solution.
So in 100 litre the molarity will be = $\dfrac{{0.1}}{{100}} = 0.0001{\text{moles/ litre}}$.
The pOH of the solution = ${\text{pOH = }} - {\text{lo}}{{\text{g}}_{{\text{10}}}}\left[ {{\text{O}}{{\text{H}}^ - }} \right]$
Hence, \[{\text{pOH}}\]=${\text{ - lo}}{{\text{g}}_{{\text{10}}}}\left[ {{{10}^{ - 3}}} \right] = 3$.
The \[{\text{pH}} = 14 - {\text{pOH}} = 14 - 3 = 11\]
Hence, the correct answer is option C.
Note: pH is a very important factor in different conditions. The pH of a reaction can even alter the rate of a reaction. The pH of water determines the solubility and the precipitation of different salts. The pH of a solution can range from 0 to 14. Where 0 is the value of for the most acidic solution and 14 is the value of the most basic solution. The pOH scale is just the opposite of the pH scale and here the value of 0 is most the most basic solution, while 14 is the value of the most acidic solution.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Business Studies: Engaging Questions & Answers for Success

Trending doubts
Why cannot DNA pass through cell membranes class 12 biology CBSE

Draw a neat and well labeled diagram of TS of ovary class 12 biology CBSE

In a human foetus the limbs and digits develop after class 12 biology CBSE

AABbCc genotype forms how many types of gametes a 4 class 12 biology CBSE

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

The correct structure of ethylenediaminetetraacetic class 12 chemistry CBSE

