The perimeter of the sector of a circle, of area 25$\pi $sq. cm. is 20 cm. Find the area of the sector.
Answer
604.5k+ views
Hint: We will first find the radius of the circle by comparing the area 25$\pi $ with the formula of the area of the circle $\pi r^2$. Then, we will calculate the arc length s of the sector using the perimeter of the sector by the formula: perimeter of the sector = 2 r + s, where r is radius and s is arc length of the sector. Then, we will calculate the required area of the sector by the formula: area = $\dfrac{\theta }{{{{360}^ \circ }}}\pi {r^2}$where $\theta = \dfrac{s}{r}$.
Complete step-by-step answer:
We are given the perimeter of the sector of the circle as 20 cm.
The area of the circle is also given as 25$\pi $sq. cm.
We are required to find the area of the sector.
Let us first find the radius of the circle. We know that the area of the circle is given by the formula:
Area of the circle: $\pi r^2$
Comparing it with the given value of area of the circle, we get
$ \Rightarrow $$\pi r^2$ = 25$\pi $
$ \Rightarrow $$r^2$ = 25
$ \Rightarrow $r = 5
Now, the perimeter of the sector is given by: 2 r + s, where r is the radius of the circle and s is the arc length of the sector. The perimeter of the sector is 20 cm.
$ \Rightarrow $20 = 2 (5) + s
$ \Rightarrow $20 = 10 + s
$ \Rightarrow $s = 10 cm
For the area of the sector, we have the formula: $\dfrac{\theta }{{{{360}^ \circ }}}\pi {r^2}$
where, $\theta = \dfrac{s}{r}$$ \Rightarrow $$\theta $= $\dfrac{{10}}{5} = 2$
putting this value in the area of the sector, we get
$ \Rightarrow $area of the sector = $\dfrac{2}{{{{360}^ \circ }}}\pi \left( {{5^2}} \right)$
In radians, 360° can be written as 2$\pi $.
$ \Rightarrow $area of the sector = $\dfrac{2}{{2\pi }}\pi 25 = 25$
Therefore, the area of the sector is 25 sq. cm.
Note: In such questions, you may go wrong while calculating for the arc length using the perimeter because you are required to find the area of the circle before that. Be careful while converting the degrees into the radian form as we did for the sake of simplicity in the answer.
Complete step-by-step answer:
We are given the perimeter of the sector of the circle as 20 cm.
The area of the circle is also given as 25$\pi $sq. cm.
We are required to find the area of the sector.
Let us first find the radius of the circle. We know that the area of the circle is given by the formula:
Area of the circle: $\pi r^2$
Comparing it with the given value of area of the circle, we get
$ \Rightarrow $$\pi r^2$ = 25$\pi $
$ \Rightarrow $$r^2$ = 25
$ \Rightarrow $r = 5
Now, the perimeter of the sector is given by: 2 r + s, where r is the radius of the circle and s is the arc length of the sector. The perimeter of the sector is 20 cm.
$ \Rightarrow $20 = 2 (5) + s
$ \Rightarrow $20 = 10 + s
$ \Rightarrow $s = 10 cm
For the area of the sector, we have the formula: $\dfrac{\theta }{{{{360}^ \circ }}}\pi {r^2}$
where, $\theta = \dfrac{s}{r}$$ \Rightarrow $$\theta $= $\dfrac{{10}}{5} = 2$
putting this value in the area of the sector, we get
$ \Rightarrow $area of the sector = $\dfrac{2}{{{{360}^ \circ }}}\pi \left( {{5^2}} \right)$
In radians, 360° can be written as 2$\pi $.
$ \Rightarrow $area of the sector = $\dfrac{2}{{2\pi }}\pi 25 = 25$
Therefore, the area of the sector is 25 sq. cm.
Note: In such questions, you may go wrong while calculating for the arc length using the perimeter because you are required to find the area of the circle before that. Be careful while converting the degrees into the radian form as we did for the sake of simplicity in the answer.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

