
The peak emission from a black body at a certain temperature occurs at a wavelength of . On increasing its temperature, the total radiation emitted is increased 81 times. At the initial temperature when the peak radiation from the black body is incident on a metal surface, it does not cause any photoemission from the surface. After the increase in temperature, the peak radiation from the black body caused photoemission. To bring these photoelectrons to rest, potential equivalent excitation energy between n=2 and n=3 Bohr levels of hydrogen atoms is required. Find the work function of the metal.
Answer
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Hint: Here using two relationships that is energy radiated is directly proportional to temperature and there is one particular wavelength above which there is no photoelectric emission.
Complete step by step answer:
Let and be the initial and final rate of emission at temperature and respectively.
Using Stefan’s law, the total amount of heat energy E radiated per second per unit area of the surface of a perfectly black body is directly proportional to the fourth power of its absolute temperature T.
Now represented in terms of the equation,
After removing proportionality we get,
Where is called the Stefan’s constant. Its value is
Now we will consider Stefan’s equation for our further calculations.
Then, and
From the question, after increasing the temperature heat energy emitted is 81 times the initial energy emitted at temperature . Then,
Now substitute the values of and in the above equation, we get
gets cancel out from above equation then remaining equation is,
81 can also be written as then,
Now taking fourth root on both sides we get,
From this we can say that temperature has increased 3 times more than the initial temperature T1.
Let us find the emission from a black body at a temperature T2 occurs at a wavelength of .
We have emission from a black body at a temperatureT1occurs at a wavelength of . But at this wavelength, there is no photoelectric emission. Because we know that the wavelength of the incident radiation must be less than the threshold wavelength.
Therefore now we need to calculate ,
According to Wien’s displacement law, the product of wavelength ( )at which maximum energy is emitted and absolute temperature (T) of the black body is always constant.
That is constant=
Now consider a given problem we get
At this wavelength, there is the emission of black body radiation from the surface.
Now let us calculate the work function,
Consider Einstein’s photoelectric equation, ………… (1)
is the work function.
We have
Then, equation (1) becomes,
Where E is the energy of the incident radiation, that is Where is frequency of incident radiation is the Planck’s constant.
…………… (2)
Next we will calculate the value of ,
…………. (3)
On substituing value,
On simplification, we get
Similarly,
On substituting value,
On simplification, we get
Now apply these values in equation (3),
Now substituting all the values in equation(2) we get,
Here is divided because to convert energy E from joule to eV.
Therefore, the final answer is in eV.
The work function is 2.24eV.
Additional information:
The minimum energy required by an electron to overcome the surface barrier of the metal is called the work function of the metal. The minimum energy required for an electron to just escape from the metal surface is called “work function”. It is denoted by .
The work function depends on:
(i) the nature of the metal
(ii) the conditions of the metal surface
According to Einstein’s photoelectric equation,
When a light is incident on a metal, the photons having energy collide with electrons at the surface of the metal. During these collisions, the energy of the photon is completely transferred to the electron. If this energy is sufficient, the electrons are ejected out of the metal instantaneously. The minimum energy needed for the electron to come out of the metal surface is called work function. If the energy of the incident photon exceeds the work function ,the electrons are emitted with a maximum kinetic energy.
Note:
In this type of question, the main thing is the threshold wavelength that is a certain value of incident wavelength above which there is no emission of photoelectrons. In this question, the first wavelength does not create photoelectric emission. Therefore we need to find a second wavelength.
Complete step by step answer:
Let
Using Stefan’s law, the total amount of heat energy E radiated per second per unit area of the surface of a perfectly black body is directly proportional to the fourth power of its absolute temperature T.
Now represented in terms of the equation,
After removing proportionality we get,
Where
Now we will consider Stefan’s equation for our further calculations.
Then,
From the question, after increasing the temperature heat energy emitted is 81 times the initial energy emitted at temperature
Now substitute the values of
81 can also be written as
Now taking fourth root on both sides we get,
From this we can say that temperature has increased 3 times more than the initial temperature T1.
Let us find the emission from a black body at a temperature T2 occurs at a wavelength of
We have emission from a black body at a temperatureT1occurs at a wavelength of
Therefore now we need to calculate
According to Wien’s displacement law, the product of wavelength (
That is
Now consider a given problem we get
At this wavelength, there is the emission of black body radiation from the surface.
Now let us calculate the work function,
Consider Einstein’s photoelectric equation,
We have
Then, equation (1) becomes,
Where E is the energy of the incident radiation, that is
Next we will calculate the value of
On substituing
On simplification, we get
Similarly,
On substituting
On simplification, we get
Now apply these values in equation (3),
Now substituting all the values in equation(2) we get,
Here
Therefore, the final answer is in eV.
Additional information:
The minimum energy required by an electron to overcome the surface barrier of the metal is called the work function of the metal. The minimum energy required for an electron to just escape from the metal surface is called “work function”. It is denoted by
The work function depends on:
(i) the nature of the metal
(ii) the conditions of the metal surface
According to Einstein’s photoelectric equation,
When a light is incident on a metal, the photons having energy
Note:
In this type of question, the main thing is the threshold wavelength that is a certain value of incident wavelength above which there is no emission of photoelectrons. In this question, the first wavelength does not create photoelectric emission. Therefore we need to find a second wavelength.
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