The oxide of iodine used in the estimation of carbon monoxide is:
A. ${I_2}{O_4}$
B. ${I_2}{O_6}$
C. ${I_2}{O_7}$
D. ${I_2}{O_5}$
Answer
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Hint: Iodine pentoxide, ${I_2}{O_5}$ is sometimes used to remove carbon monoxide from the air by forming carbon dioxide and iodine
$5CO + {I_2}{O_5} \to {I_2} + 5C{O_2}$
Complete step by step answer:
Iodine peroxide, ${I_2}{O_5}$ is an important reagent for the determination of carbon monoxide (CO) in the gaseous mixtures. The treatment of solid iodine pentoxide $({I_2}{O_5})$ with gaseous carbon monoxide (CO) in the presence of air gives carbon dioxide $(C{O_2})$ and solid iodine $({I_2})$.
$5CO + {I_2}{O_5} \to {I_2} + 5C{O_2}$
The reaction proceeds rapidly and quantitatively at room temperature and the iodine $({I_2})$ that is formed in the reaction is titrated using sodium thiosulphate.
The other oxides of iodine re not well characterized,
Thus, Iodine pentoxide $({I_2}{O_5})$ is used in the estimation of carbon monoxide.
Therefore, the correct answer is option (D).
Note: Of all the oxides of iodine present, Iodine pentoxide is the most stable and useful. Iodine pentoxide is the oxide of iodine with the chemical formula ${I_2}{O_5}$ . This iodine oxide is the anhydride of ionic solid. It is the white, crystalline solid. It is produced by dehydrating iodic acid at 200-degree Celsius in a stream of dry air. Its IUPAC name is Diiodine pentoxide and other names are Iodine(V) oxide and Iodic anhydride. Its molar mass is 333.81 g/mol. Its density is 4.980 $\dfrac{{gm}}{{c{m^3}}}$ . Its melting point is 300-degree Celsius and it is soluble in water, reforming iodic acid and is also soluble in and nitric acid. It is insoluble in ethanol, ether and $C{S_2}$ . Its structure is bent with an \[I-O-I\] angle of 139.2 degrees.
$5CO + {I_2}{O_5} \to {I_2} + 5C{O_2}$
Complete step by step answer:
Iodine peroxide, ${I_2}{O_5}$ is an important reagent for the determination of carbon monoxide (CO) in the gaseous mixtures. The treatment of solid iodine pentoxide $({I_2}{O_5})$ with gaseous carbon monoxide (CO) in the presence of air gives carbon dioxide $(C{O_2})$ and solid iodine $({I_2})$.
$5CO + {I_2}{O_5} \to {I_2} + 5C{O_2}$
The reaction proceeds rapidly and quantitatively at room temperature and the iodine $({I_2})$ that is formed in the reaction is titrated using sodium thiosulphate.
The other oxides of iodine re not well characterized,
Thus, Iodine pentoxide $({I_2}{O_5})$ is used in the estimation of carbon monoxide.
Therefore, the correct answer is option (D).
Note: Of all the oxides of iodine present, Iodine pentoxide is the most stable and useful. Iodine pentoxide is the oxide of iodine with the chemical formula ${I_2}{O_5}$ . This iodine oxide is the anhydride of ionic solid. It is the white, crystalline solid. It is produced by dehydrating iodic acid at 200-degree Celsius in a stream of dry air. Its IUPAC name is Diiodine pentoxide and other names are Iodine(V) oxide and Iodic anhydride. Its molar mass is 333.81 g/mol. Its density is 4.980 $\dfrac{{gm}}{{c{m^3}}}$ . Its melting point is 300-degree Celsius and it is soluble in water, reforming iodic acid and is also soluble in and nitric acid. It is insoluble in ethanol, ether and $C{S_2}$ . Its structure is bent with an \[I-O-I\] angle of 139.2 degrees.
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