The number of moles of solute present in 600ml of 0.05 m solution is:
Answer
613.8k+ views
Hint: Use the formula of molarity and put the given quantities in formula to find the unknown
Formula used : Molarity= Number of moles /Volume(ml)$ \times $1000
Complete step by step answer:
Find the given quantities
Given: Molarity =0.05M
Volume=600ml
Let the number of moles be $x$ and put all the given values in formula
$0.05 = \dfrac{{x \times 1000}}{{600}}$
Cross multiply the equation
$
600 \times 0.05 = x \times 1000 \\
30 = x \times 1000 \\
$
Find the value of $x$
$x = \dfrac{{30}}{{1000}} = 0.03mol$
Note:
Molarity and Molality are two similar looking confusing terms . Molarity is the number of moles of solute present in 1L of solution. Molality is the number of moles of solute present in 1Kg of solvent.
Normality is another term used for expressing the concentration of a solution. As per the standard definition , normality is defined as the number of mole or gram equivalent of solute present in 1 liter of solution. It is denoted by ‘N’. in simple words, normality is equal to molality divided by valency. Or we can say that normality is the number of moles of solute present in the equivalent weight of solution. Equivalent weight is molar mass of a substance divided by the valency.
Formula used : Molarity= Number of moles /Volume(ml)$ \times $1000
Complete step by step answer:
Find the given quantities
Given: Molarity =0.05M
Volume=600ml
Let the number of moles be $x$ and put all the given values in formula
$0.05 = \dfrac{{x \times 1000}}{{600}}$
Cross multiply the equation
$
600 \times 0.05 = x \times 1000 \\
30 = x \times 1000 \\
$
Find the value of $x$
$x = \dfrac{{30}}{{1000}} = 0.03mol$
Note:
Molarity and Molality are two similar looking confusing terms . Molarity is the number of moles of solute present in 1L of solution. Molality is the number of moles of solute present in 1Kg of solvent.
Normality is another term used for expressing the concentration of a solution. As per the standard definition , normality is defined as the number of mole or gram equivalent of solute present in 1 liter of solution. It is denoted by ‘N’. in simple words, normality is equal to molality divided by valency. Or we can say that normality is the number of moles of solute present in the equivalent weight of solution. Equivalent weight is molar mass of a substance divided by the valency.
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