Question

The number of ions formed when tetraamine copper (II) sulphate is dissolved in water is
A.One
B.Four
C.Two
D.Zero

Answer 1

Hint: Basically, tetraamine copper (II) sulphate is the salt with the formula $[Cu{(N{H_3})_4}]S{O_4}.{H_2}O$ Moreover, the deep blue crystalline solid tends to hydrolyze and evolve ammonia upon standing in air. So, to solve this question, we need to write the chemical reaction and then determine the number of ions formed.

Complete step by step answer:
The salt of tetraamine copper is a dark blue to purple solid of the metal complex $[Cu{(N{H_3})_4}]S{O_4}.{H_2}O$ .It is further related two Schweizer’s reagent, which is used for the production of cellulose fibers in the production of rayon. It is fairly soluble in water. Now, let’s talk about its structure and geometry. It is a complex ion which has a square planar pyramidal molecular geometry. Moreover, in 1967, Saito and Kanda conducted proton nuclear magnetic resonance studies on this material in the paramagnetic and ordered state.
Now, let’s see the number of ions formed when tetraamine copper (II) sulphate is dissolved in two.
 $[Cu{(N{H_3})_4}]S{O_4} \to {[Cu{(N{H_3})_4}]^{2 + }} + S{O_4}^{2 - }$
So, as we have seen that two ions are formed. Further, $[Cu{(N{H_3})_4}]$ is a complex ion and retains its identity in the aqueous solution.
Hence, option C is correct.

Note:The deep blue color of tetraamine complex is found in brass and copper alloys, where the attack from ammonia takes place which further leads to cracking. So, this type of corrosion is generally known as season cracking.