
The natural forces to move the sphere A and B on a \[30^\circ \] smooth incline are 25 N and 5N.The spring constant is $100{\text{ }}N{m^{ - 1}}$ .Find the elongation in the spring ($g = 10{\text{ }}m{s^{ - 2}}$)
Answer
489.9k+ views
Hint: In order to solve the question, we will first make the free body diagram of the figure given in the question then we will find the natural forces applied on the balls while moving on the incline plane after then we will find the acceleration to check the elongation of both spheres.
Formula Used:
$F = ma$
F refers to force
M refers to mass
A refers to acceleration
Complete step by step solution:
In the question we are given to sphere on an inclined plane connected to each other and on both of the sphere force is applied and we have to find the elongation in the spring
it is also given that the natural forces are only applied on the sphere to move which means only gravitation force is applied and it is also mentioned that value of $g = 10{\text{ }}m{s^{ - 2}}$
it is also given in the diagram that coefficient of friction is zero which means the surface of the incline plane is frictionless
angle of inclination of inclined plane = \[30^\circ \]
force applied on spring A = 25 N
force applied on spring B = 5 N
spring constant is $100{\text{ }}N{m^{ - 1}}$
This is free body diagram of the spheres on which gravitational force is applied
On both the spheres A and B due same inclination same force is applied gravitational force on the downward direction and in the direction of falling force is applied
According to FDB
Sphere A
${F_A} = {M_A}g\sin 30^\circ $
force applied on spring A = 25 N
$25N = {M_A}g\sin 30^\circ $
Acceleration applied is \[g\sin 30^\circ \] on Sphere A
Sphere B
${F_B} = {M_B}g\sin 30^\circ $
force applied on spring A = 5 N
$5N = {M_B}g\sin 30^\circ $
Acceleration applied is \[g\sin 30^\circ \] on Sphere B
As we can see that the both spheres have the same acceleration so both of them are sliding freely, that’s why there will be no elongation
Note: Many of the people will be confused by the extra values and the variable given in the question for example spring constant is given in the question but it has no use as well as forces also does play any part in the calculation it only factorizes that the mass of both spheres are different but both of them are moving with the same acceleration.
Formula Used:
$F = ma$
F refers to force
M refers to mass
A refers to acceleration
Complete step by step solution:
In the question we are given to sphere on an inclined plane connected to each other and on both of the sphere force is applied and we have to find the elongation in the spring
it is also given that the natural forces are only applied on the sphere to move which means only gravitation force is applied and it is also mentioned that value of $g = 10{\text{ }}m{s^{ - 2}}$
it is also given in the diagram that coefficient of friction is zero which means the surface of the incline plane is frictionless
angle of inclination of inclined plane = \[30^\circ \]
force applied on spring A = 25 N
force applied on spring B = 5 N
spring constant is $100{\text{ }}N{m^{ - 1}}$
This is free body diagram of the spheres on which gravitational force is applied
On both the spheres A and B due same inclination same force is applied gravitational force on the downward direction and in the direction of falling force is applied
According to FDB
Sphere A
${F_A} = {M_A}g\sin 30^\circ $
force applied on spring A = 25 N
$25N = {M_A}g\sin 30^\circ $
Acceleration applied is \[g\sin 30^\circ \] on Sphere A
Sphere B
${F_B} = {M_B}g\sin 30^\circ $
force applied on spring A = 5 N
$5N = {M_B}g\sin 30^\circ $
Acceleration applied is \[g\sin 30^\circ \] on Sphere B
As we can see that the both spheres have the same acceleration so both of them are sliding freely, that’s why there will be no elongation
Note: Many of the people will be confused by the extra values and the variable given in the question for example spring constant is given in the question but it has no use as well as forces also does play any part in the calculation it only factorizes that the mass of both spheres are different but both of them are moving with the same acceleration.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

