
The mean values of current for one complete cycle of shown current supply is
Answer
502.8k+ views
Hint:A stream of charged particles, such as electrons or ions, passing through an electrical conductor or space is known as an electric current. It's the net rate of electric charge flow through a surface or through a control volume that's determined.
Complete step by step answer:
In an AC device, the root mean square is used to express the average current or voltage. The highest current and voltage over the square root of two are the RMS current and voltage (for sinusoidal systems). In an AC circuit, the average power is equal to the product of the RMS current and RMS voltage.
The average of any instantaneous current value on a sine wave from zero to peak and back is referred to as average current; alternating or AC current is reflected by a sine wave.The cumulative charge flown for one full loop divided by the time taken to complete the cycle, i.e. time duration T, is the mean value of an alternating current. An alternating current's magnitude varies over time, and its trajectory often reverses for a half cycle.
Calculating the area of the plot covered yields the mean current values for one complete cycle of the shown current supply.
$A = \int I dt$
The charge q corresponds to the area covered.
$q = \dfrac{1}{2}{I_o}(\dfrac{T}{2}) + {I_o}(\dfrac{T}{2})$
\[\Rightarrow q = \dfrac{3}{4}{I_o}(\dfrac{T}{2})\]
Now we know that
${i_{avg}} = \dfrac{q}{T}$
$\Rightarrow {i_{avg}} = \dfrac{{\dfrac{3}{4}{I_o}(\dfrac{T}{2})}}{T} \\
\therefore {i_{avg}}= \dfrac{3}{4}{I_o}$
Hence, the mean values of current for one complete cycle of shown current supply is $\dfrac{3}{4}{I_o}$.
Note:Charge carriers are the travelling particles, and depending on the conductor, they may be one of several kinds of particles. Electrons passing through a wire are often used as charge carriers in electric circuits. They may be electrons or holes in semiconductors. Ions carry charge in an electrolyte, while ions and electrons carry charge in plasma, an ionised gas.
Complete step by step answer:
In an AC device, the root mean square is used to express the average current or voltage. The highest current and voltage over the square root of two are the RMS current and voltage (for sinusoidal systems). In an AC circuit, the average power is equal to the product of the RMS current and RMS voltage.
The average of any instantaneous current value on a sine wave from zero to peak and back is referred to as average current; alternating or AC current is reflected by a sine wave.The cumulative charge flown for one full loop divided by the time taken to complete the cycle, i.e. time duration T, is the mean value of an alternating current. An alternating current's magnitude varies over time, and its trajectory often reverses for a half cycle.
Calculating the area of the plot covered yields the mean current values for one complete cycle of the shown current supply.
$A = \int I dt$
The charge q corresponds to the area covered.
$q = \dfrac{1}{2}{I_o}(\dfrac{T}{2}) + {I_o}(\dfrac{T}{2})$
\[\Rightarrow q = \dfrac{3}{4}{I_o}(\dfrac{T}{2})\]
Now we know that
${i_{avg}} = \dfrac{q}{T}$
$\Rightarrow {i_{avg}} = \dfrac{{\dfrac{3}{4}{I_o}(\dfrac{T}{2})}}{T} \\
\therefore {i_{avg}}= \dfrac{3}{4}{I_o}$
Hence, the mean values of current for one complete cycle of shown current supply is $\dfrac{3}{4}{I_o}$.
Note:Charge carriers are the travelling particles, and depending on the conductor, they may be one of several kinds of particles. Electrons passing through a wire are often used as charge carriers in electric circuits. They may be electrons or holes in semiconductors. Ions carry charge in an electrolyte, while ions and electrons carry charge in plasma, an ionised gas.
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