Question

The marked price of a water cooler is Rs.4650. The shopkeeper offers an off-season discount of 18% on it. Find its selling price.

Answer 1

Hint: In this question, we need to first look at some of the basic definitions of linear equations. Then we need to calculate how much the value of 18% of Rs.4650 is and then subtract this amount from the given total amount to get the result.

Complete step by step solution:
Let us look at the percentage formula.
The value of x% in y can be written as:
\[\dfrac{x}{100}\times y\]
Now, on comparing with the given values we get,
\[x=18,y=4650\]
Let us assume that the cost after discount as A.
\[\begin{align}
  & \Rightarrow A=4650-\dfrac{18}{100}\times 4650 \\
 & \Rightarrow A=4650-\left( 18\times 46.5 \right) \\
 & \Rightarrow A=4650-837 \\
 & \therefore A=Rs.3,813 \\
\end{align}\]
Hence, the selling price of the water cooler is Rs.3,813.

Note: It is important to note that the season-off discount of 18% should be calculated by first calculating how much is 18% in the total amount given and then subtract it from the total amount which gives the final selling price of the product.
We need to subtract the values of the percentage value calculated in the total amount because we were given a discount which means the offer given to the customer by decreasing the original price of the product.
The important note is that we need to subtract the percentage amount calculated from the total given amount.