
The IUPAC name of $[Ni(CO)_4]$ and $[PtCl_4]^{2−}$.
Answer
600k+ views
Hint: In this question we need to explain the given elements above in the question, as giving a brief knowledge about this compound can help us to give a brief knowledge about such kinds of elements.
Complete answer:
Nickel carbonyl (IUPAC name: tetracarbonylnickel) is the organonickel compound with the recipe $Ni(CO)_4$. This dismal fluid is the vital carbonyl of nickel. It is a middle of the road in the Mond procedure for creating extremely high-virtue nickel and a reagent in organometallic science, in spite of the fact that the Mond Process has dropped out of basic utilization because of the wellbeing perils in working with the compound. Nickel carbonyl is one of the most hazardous substances yet experienced in nickel science because of its high poisonousness, aggravated with high instability and fast skin assimilation
The IUPAC name of $Ni(CO)_4$ is Tetracarbonyl nickel (0) since the oxidation state of carbonyl ligand is 0, so Ni will also be 0 and four ligand are bonded to central metal atom and
$[PtCl_4]^{2-}$
Tetrachloroplatinate(2-)
Note: In this answer we gave a brief explanation about both the required compounds and giving an explanation can also help us to gain such a type of answer. Explananing formulae would also help in the required solution.
Complete answer:
Nickel carbonyl (IUPAC name: tetracarbonylnickel) is the organonickel compound with the recipe $Ni(CO)_4$. This dismal fluid is the vital carbonyl of nickel. It is a middle of the road in the Mond procedure for creating extremely high-virtue nickel and a reagent in organometallic science, in spite of the fact that the Mond Process has dropped out of basic utilization because of the wellbeing perils in working with the compound. Nickel carbonyl is one of the most hazardous substances yet experienced in nickel science because of its high poisonousness, aggravated with high instability and fast skin assimilation
The IUPAC name of $Ni(CO)_4$ is Tetracarbonyl nickel (0) since the oxidation state of carbonyl ligand is 0, so Ni will also be 0 and four ligand are bonded to central metal atom and
$[PtCl_4]^{2-}$
Tetrachloroplatinate(2-)
Note: In this answer we gave a brief explanation about both the required compounds and giving an explanation can also help us to gain such a type of answer. Explananing formulae would also help in the required solution.
Recently Updated Pages
A man running at a speed 5 ms is viewed in the side class 12 physics CBSE

State and explain Hardy Weinbergs Principle class 12 biology CBSE

Which of the following statements is wrong a Amnion class 12 biology CBSE

Two Planoconcave lenses 1 and 2 of glass of refractive class 12 physics CBSE

The compound 2 methyl 2 butene on reaction with NaIO4 class 12 chemistry CBSE

Bacterial cell wall is made up of A Cellulose B Hemicellulose class 12 biology CBSE

Trending doubts
What are the major means of transport Explain each class 12 social science CBSE

Which are the Top 10 Largest Countries of the World?

Draw a labelled sketch of the human eye class 12 physics CBSE

Explain sex determination in humans with line diag class 12 biology CBSE

The pH of the pancreatic juice is A 64 B 86 C 120 D class 12 biology CBSE

Give 10 examples of unisexual and bisexual flowers

